Gravitation Tes...

At what altitude (h) above the earth's surface would the acceleration due to gravity be one fourth of its value at the earths surface?

A particle weights 120N on the surface of the earth. At what height above the earth's surface will its weight be 30N? Radius of the earth is 6400 km.

A particle is taken to a height $$R$$ above the surface, where $$R$$ is the radius of the earth. The acceleration due to gravity there is:

The altitude at which the weight of a body is only $$64\%$$ of its weight on the surface of the earth is (Radius of the earth $$6,400km$$)

The height at which the weight of a body becomes $$\dfrac{1}{16^th}$$,its weight on the surface of earth (radius R), is :-

If the radius of the earth is $$6400km$$, the height above the surface of the earth ,where the value of acceleration due to gravity will be $$1\%$$ of its value from the surface of the earth is  

Escape velocity on the earth is

A body of mass m is taken from earth's surface to q a height equal to radius of earth . the change in potential will be 

At what height above the surface of earth, acceleration due to gravity is $$\Bigg \lgroup \frac{1}{8} \Bigg \rgroup^{th}$$ of its value at the surface of earth: ($$R_e$$ = Radoius of earth)

Earth can be considered as uniform solid sphere of radius $$R. g_{1}$$ and $$g_{2}$$ be acceleration due to gravity at points $$R/2$$ below the surface and $$R/2$$ above the surface of earth respectively. Then $$\dfrac {g_{1}}{g_{2}}$$ equals to