Gravitation Tes...

Calculate the ratio of  weights of a body when it is (radius of the Earth is 6400km.)

If the Earth were to shrink so that the density becomes eight times the present density without any change in its mass, then 'the weight of a person on the surface of Earth 

 The height at which the acceleration due to gravity becomes $$g/9$$ (where $$g=the$$ acceleration due to gravity on the surface of the earth) in terms of $$R$$, the radius of the earth, is

If the change in the value of g at a height h above the surface of the earth is same as at depth below the surface of the earth, then (h >>R)

A hole is drilled from the surface of earth to its centre. A particle is dropped from rest at the surface of earth. The speed of the particle when it reaches the centre of the earth in terms of its escape velocity on the surface of earth $$v_{e}$$ is :

A tunnel is dug along a diameter of the planet. A particle is dropped from the surface of the planet and reaches the center of the planet with speed $$V$$. The escape velocity from surface of planet is

The weight of the body at earth's surface is W. At a depth halfway to the center of the earth, it will be? (assuming uniform density in the earth)

The magnitude of gravitational potential energy of a body at a distance 'r' from the center of the earth is V. Its weight at a distance '2r' from the center of the earth is

If the acceleration due to gravity at a height $$h$$ from the surface of the earth is $$96\%$$ less than its value on the surface, then $$h$$ is (where $$R$$ is radius of the earth). 

Ratio of time period of satellites orbiting around earth at a  distance of about 9r and 4r from earth surface is : ( where r is the radius of earth)