Mechanical Properties of Solids Test

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Mechanical Properties of Solids Test - 53

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Weekly Quiz Competition

Question 1
1 / -0

Plastic deformation in a material begins at

A
Q point

B
Yield point

C
Proportionality limit

D
Elastic limit

Solution

Beyond the elastic limit, permanent deformation will occur. The elastic limit is therefore the lowest stress point at which permanent deformation can be measured. At yield point, permanent deformation occurs or the substance becomes plastic.

The correct option is option (b)
Question 2
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Substances that elongate considerably and undergo plastic deformation before they break are known as

A
brittle substances

B
breakable substances

C
ductile substances

D
all of these

Solution

Substances that elongate considerably and undergo plastic deformation before they break are known as ductile substances
Question 3
1 / -0

Elasticity is defined as the ability of a body to

A
Resist linear motion in a hard surface

B
Resist rolling motion in a hard surface

C
Resist a distorting influence and to return to its original size and shape when that influence or force is removed.

D
Resist electric current in a magnetic field

Solution

Elasticity is defined as the ability of a body to resist a distorting influence and to return to its original size and shape when that influence or force is removed.
Question 4
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Which of the following is the dimension of Bulk Modulus?

A
$$[M^1L^{-1}T^{-1}]$$

B
$$[M^1L^{-1}T^{-2}]$$

C
$$[M^1L^{1}T^{2}]$$

D
$$[M^1L^{1}T^{-1}]$$

Solution

Bulk modulus is pressure/volumetric strain. The strain dosen't have any units and hence bulk's modulus takes the units of pressure. Thus, dimensions of bulk's modulus is $$[B]=[MLT^{-2}]/[L^2] =[ML^{-1}T^{-2}]$$

The correct option is (b)
Question 5
1 / -0

Longitudinal strain is calculated using the formula

A
Change in length/ original length

B
Original length/Change in length

C
Original length $$\times $$ Change in length

D
Original length - Change in length

Solution

Longitudinal strain is calculated using the formula Change in length/ original length

The correct option is option (a)
Question 6
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The difference between pressure and stress is

A
pressure and stress have different units

B
pressure and stress have different dimensions

C
Force cannot be determined using stress, but in pressure it can be done

D
Pressured is applied to a body, while stress is induced

Solution

Pressure is applied on an object to compress it, while stress is induced inside the body and acts opposite to the direction of the pressure applied

The correct option is option (d)
Question 7
1 / -0

A wire has a tensile strength of 70MPa, and breaks under 100N of force. What is the cross-sectional area of the wire just before breaking?

A
$$14.2 \times 10^{-6} m^2$$

B
$$1.42 \times 10^{-6} m^2$$

C
$$ 1.42 \times 10^{-3} m^2$$

D
$$ 1.42 \times 10^{-2} m^2$$

Solution

The tensile strength = stress = force/area

Thus, $$area = Force/ Stress =100/ (70 \times 10^6) = 1.42 \times 10^{-6} m^2$$

The correct option is option (b)
Question 8
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Which one of the following is true about Bulk Modulus of elasticity?

A
It is the ratio of compressive stress to volumetric strain

B
It is the ratio of compressive stress to linear strain

C
It is the ratio of tensile stress to volumetric strain

D
It is the ratio of tensile stress to linear strain

Solution

Bulk Modulus k is related to the compression of a liquid and the decrease in volume per unit volume. It is the ratio of compressive stress to the volumetric strain.

The correct option is (a)
Question 9
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A force of 10 N is applied to an object, whose area is $$5 cm^2$$ at an angle of 30 degrees with the vertical. What kind of stress can be found from this data

A
Normal and areal stress can be found

B
only normal stress can be found

C
only areal stress can be found

D
Stress cannot be found from this data, since applied force is neither along the horizontal or vertical

Solution

The applied force can be resolved in to two components namely,
F cos 30 along the horizontal and F sin 30 along the vertical

Thus, the normal stress can be determined as F sin 30 x Area of cross section
The areal stress can be determined using F cos 30 x Area perpendicular to horizontal axis

Thus, the correct option is (a)
Question 10
1 / -0

A steel wire is suspended from a fixed end, while the other end is loaded with a weight W. This produced an extension x. As the weight is increased, the extension was also increased. A plot of extension vs load within elastic limits will give rise to

A
a curve

B
an ellipse

C
a straight line

D
a hyperbola

Solution

The plot is between extension and the force (mg), which will be a straight line

The correct option is option (c)

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Mechanical Properties of Solids Test - 53

Result

Mechanical Properties of Solids Test - 53

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SHARING IS CARING

Question 1

Q point

Yield point

Proportionality limit

Elastic limit

Solution

Question 2

brittle substances

breakable substances

ductile substances

all of these

Solution

Question 3

Resist linear motion in a hard surface

Resist rolling motion in a hard surface

Resist a distorting influence and to return to its original size and shape when that influence or force is removed.

Resist electric current in a magnetic field

Solution

Question 4

$$[M^1L^{-1}T^{-1}]$$

$$[M^1L^{-1}T^{-2}]$$

$$[M^1L^{1}T^{2}]$$

$$[M^1L^{1}T^{-1}]$$

Solution

Question 5

Change in length/ original length

Original length/Change in length

Original length $$\times $$ Change in length

Original length - Change in length

Solution

Question 6

pressure and stress have different units

pressure and stress have different dimensions

Force cannot be determined using stress, but in pressure it can be done

Pressured is applied to a body, while stress is induced

Solution

Question 7

$$14.2 \times 10^{-6} m^2$$

$$1.42 \times 10^{-6} m^2$$

$$ 1.42 \times 10^{-3} m^2$$

$$ 1.42 \times 10^{-2} m^2$$

Solution

Question 8

It is the ratio of compressive stress to volumetric strain

It is the ratio of compressive stress to linear strain

It is the ratio of tensile stress to volumetric strain

It is the ratio of tensile stress to linear strain

Solution

Question 9

Normal and areal stress can be found

only normal stress can be found

only areal stress can be found

Stress cannot be found from this data, since applied force is neither along the horizontal or vertical

Solution

Question 10

a curve

an ellipse

a straight line

a hyperbola

Solution

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