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Principles of Inheritance and Variation Test - 22

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Principles of Inheritance and Variation Test - 22
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  • Question 1
    1 / -0

    All genes located on the same chromosome:

    Solution

    Morgan showed that genes located on the same chromosome formed one linkage group. But linkage or no linkage depends on proximity of two genes. Genes which are closer show more likelihood of linkage.

  • Question 2
    1 / -0

    Conditions of a karyotype 2n +1, 2n –1 and 2n + 2, 2n – 2 are called:

    Solution

    Failure of segregation of chromatids during cell division cycle results in gain or loss of chromosome. This condition is called aneuploidy.

  • Question 3
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    Distance between the genes and percentage of recombination shows

    Solution

    Chances of recombination decreases with increased distance between genes. Hence there is an inverse relationship between the two.

  • Question 4
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    If a genetic disease is transferred from a phenotypically normal but carrier female to only some of the male progeny, the disease is :

    Solution

    In this case, the defective gene is present on the X-chromosome but the disease is manifested in men and women are carriers. So, it is a sex-linked recessive disease. Haemophilia is one example and is also referred to as X-linked recessive disease.

  • Question 5
    1 / -0

    In sickle cell anaemia glutamic acid is replaced by valine. Which one of the following triplets codes for valine?

    Solution

    The substitution of amino acid in the globin protein results due to the single base substitution at the sixth codon of the beta globin gene from GAG to GUG. Condon GUG codes for valine which results in sickle cell anaemia.

  • Question 6
    1 / -0

    Person having genotype \( I^A I^B \) would show the blood group as AB. This is because of:

    Solution

    When \(F_1\) generation resembles both parents, this is called co-dominance. This is often seen in ABO blood grouping. Since both A and B sugars are dominant, hence it results in AB blood group.

  • Question 7
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    \(ZZ\over ZW\) type of sex determination is seen in:

    Solution

    This type of sex determination is seen in birds. The female has a ZW combination while the male has ZZ combination.

  • Question 8
    1 / -0

    A cross between two tall plants resulted in offspring having few dwarf plants. What would be the genotypes of both the parents?

    Solution

    In case of TT and Tt; all offspring would be tall (TT, Tt). In case of option ‘c’ no gene for dwarf is present, so all offspring will be tall. In case of option ‘d’ one of the parent plant is dwarf, so it is incorrect. In case of option ‘b’ most of the offspring will be tall and a few will be dwarf (TT, Tt, tt).

  • Question 9
    1 / -0

    In a dihybrid cross, if you get 9:3:3:1 ratio it denotes that :

    Solution

    This shows the perfect dihybrid ratio according to Mendel. Hence, the alleles of two genes are segregating independently.

  • Question 10
    1 / -0

    Which of the following will not result in variations among siblings?

    Solution

    Linkage happens in all cases whenever two genes are located on the same chromosome and are close to each other. Thus, linkage has nothing to do with variation.

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