Principles of Inheritance and Variation Test

Question 1
1 / -0

An experiment was performed to test the ability of one wild type and four mutant strains of E.coli bacteria to grow in either minimal media or media that was supplemented with various amino acids.

Supplement None Arginine
Wild-type $$+$$ $$+$$
Strain 1 $$-$$ $$+$$
Strain 2 $$-$$ $$-$$
Strain 3 $$-$$ $$-$$
Strain 4 $$+$$ $$+$$

Supplement Threonine Histidine
Wild-type $$+$$ $$+$$
Strain 1 $$-$$ $$-$$
Strain 2 $$+$$ $$-$$
Strain 3 $$-$$ $$+$$
Strain 4 $$+$$ $$+$$
A $$\left(+\right)$$ sign indicates growth and a $$\left(-\right)$$ sign indicates no growth.
Which of the following is true for mutation in strain 4?

A
Renders it dormant

B
Does not affect its ability to synthesize amino acids

C
Causes it to become haploid

D
Is identical to that in strain 1

E
None of the above

Question 2
1 / -0

An experiment was performed to test the ability of one wild type and four mutant strains of E.coli bacteria to grow in either minimal media or media that was supplemented with various amino acids.

Supplement None Arginine
Wild-type $$+$$ $$+$$
Strain 1 $$-$$ $$+$$
Strain 2 $$-$$ $$-$$
Strain 3 $$-$$ $$-$$
Strain 4 $$+$$ $$+$$

Supplement Threonine Histidine
Wild-type $$+$$ $$+$$
Strain 1 $$-$$ $$-$$
Strain 2 $$+$$ $$-$$
Strain 3 $$-$$ $$+$$
Strain 4 $$+$$ $$+$$
A $$\left(+\right)$$ sign indicates growth and a $$\left(-\right)$$ sign indicates no growth.
Which of the following amino acids are not required by strain 3 to grow?

A
Arginine and histidine

B
Threonine and histidine

C
Histidine only

D
Arginine and threonine

E
Threonine only

Question 3
1 / -0

The given pedigree depicts a rare disorder through three generations of a family.

The number of females in generation II that passed the disorder to their offspring are?

A
0

B
1

C
2

D
3

E
4

Question 4
1 / -0

A child is born with albinism, an inability to produce or deposit the pigment protein, melanin, in skin cells, as well as other pigment-containing cells of the body. His parents do not display the trait of albinism.
How is this possible?

A
The child has only one allele for skin pigmentation, though his parents each have two. Having fewer genes produces his albino characteristics.

B
A spontaneous mutation, not present in either parent, has resulted in the child producing the albino protein. The albino protein displaces the normal melanin.

C
The normal DNA from both parents has combined to produce a new form of DNA in the child. This abnormal DNA codes for the albino protein.

D
The parents each have one normal DNA allele and one that codes for albinism. The parents produce enough normal melanin protein to allow normal skin color, but the child cannot.

Question 5
1 / -0

Mendel performed his experiment on garden pea species and gave rules of heridity. Give the scientific name of the species.

A
Zea mays

B
Pisum sativum

C
Phaseolus mungo

D
Rana tigrina

Question 6
1 / -0

Based on the given pedigree, the individual III-5 will have _______ genotype.

A
Carrier

B
Unaffected

C
Homozygous recessive

D
Homozygous dominant

E
Heterozygous

Question 7
1 / -0

The tumor suppressor gene APC, when mutant, causes a precancerous condition called familial adenomatous polyposis (FAP). FAP has autosomal dominant inheritance.
What is the probability that two individuals who are heterozygous for the APC mutation would have four children, all without the APC mutation?

A
1/64

B
0.25

C
1/16

D
0.125

E
0.5

Question 8
1 / -0

According to the chromosomal theory of inheritance, which of the following type of cell division contributes maximum for recombination and genetic variation?

A
Meiosis

B
Mitosis

C
Amitosis

D
Both A and B

Question 9
1 / -0

In a pea plant, the yellow colour of the seed dominates over the green colour. The genetic make up of the green colour of the seed can be shown as _______

A
GG

B
Gg

C
Yy

D
yy

Question 10
1 / -0

Name the scientist who converted Mendel's conclusions into principles of heredity

A
De Vries

B
Tschermak-seysenegg

C
Carl Correns

D
T. H. Morgan

Submit Test

Principles of I...

Question 1

Renders it dormant

Does not affect its ability to synthesize amino acids

Causes it to become haploid

Is identical to that in strain 1

None of the above

Question 2

Arginine and histidine

Threonine and histidine

Histidine only

Arginine and threonine

Threonine only

Question 3

0

1

2

3

4

Question 4

The child has only one allele for skin pigmentation, though his parents each have two. Having fewer genes produces his albino characteristics.

A spontaneous mutation, not present in either parent, has resulted in the child producing the albino protein. The albino protein displaces the normal melanin.

The normal DNA from both parents has combined to produce a new form of DNA in the child. This abnormal DNA codes for the albino protein.

The parents each have one normal DNA allele and one that codes for albinism. The parents produce enough normal melanin protein to allow normal skin color, but the child cannot.

Question 5

Zea mays

Pisum sativum

Phaseolus mungo

Rana tigrina

Question 6

Carrier

Unaffected

Homozygous recessive

Homozygous dominant

Heterozygous

Question 7

1/64

0.25

1/16

0.125

0.5

Question 8

Meiosis

Mitosis

Amitosis

Both A and B

Question 9

GG

Gg

Yy

yy

Question 10

De Vries

Tschermak-seysenegg

Carl Correns

T. H. Morgan

User

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