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Molecular Basis of Inheritance Test - 54

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Molecular Basis of Inheritance Test - 54
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  • Question 1
    1 / -0
    Which major concept of genetics was illustrated in the model designed by Watson and Crick?

    Solution
    Watson and Crick proposed a double helical structure of DNA which was based upon the results of Wilkins that shows from x-ray crystallography the structure of DNA.
     Watson and Crick proposed that the structure is made up of the backbone of sugar and phosphate and bases are present in a right angle to it. The structure arranges itself in the form of a double helical structure of DNA. The structure was based upon the results of the X-ray crystallography which showed the equal amount of distance between the helical structures.
    So, the correct option is 'DNA exhibits a double helix structure'
  • Question 2
    1 / -0
    Which best describes the process of DNA replication?
    Solution
    DNA replication in eukaryotes is multi-replicon i.e., it has many origins of replication. So multiple bubbles are formed and then fuse which results in speeding up the replication of long  DNA molecule. Inside the replication bubble, the Y-shaped replication fork is formed from where the replication process starts and proceeds bidirectionally. Thus, the correct answer is option A.
  • Question 3
    1 / -0
    Which of the following does not describe a correct function of DNA polymerase?
    Solution
    DNA polymerase is an enzyme used in the replication of DNA. It ads the DNA primers to the parent chain. This enzyme acts in the 5'-3 direction and thus forms lading stand on the chain that has 3'5' direction.
    There are 3 DNA polymerases in use from which only the DNA polymerase II helps in replication and rest of the two are used in the DNA proofreading.

    So, the correct option is 'It adds RNA nucleotides along the DNA template in transcription.'
  • Question 4
    1 / -0
    The genetic code of a segment of DNA reads $$3$$ TTCGGGTAGAAA $$5$$. A mutation occurs between the second and third base where an extra cytosine is added.
    What would be the resulting amino acids that would be translated from the gene?

    Solution
    • Only 61 triplets or codons code for amino acids.
    • 3 stop codons (aka nonsense codons or terminator codons) UUA UAG UGA.
    • The code is a degenerative code.
    • There is no punctuation between each codon.
    • The reading of mRNA is always in the same direction 5' to 3'
     When reading from the chart, we find that the addition of extra cytosine will lead to a change in the amino acid sequence and the new sequence will be lysine-alanine-histidine and leucine.

    So, the correct option is 'Lysine-Alanine-Histidine-Leucine'
  • Question 5
    1 / -0
    Lily has .......... more DNA than human genome.
    Solution
    The main aim of the Human Genome Project was to determine the sequence of 3.2 billion base pairs of Human Genome and to identify their functions.
    It was found that Human Genome contains around 30,000 jeans and 99.9% of nucleotide bases and all human beings are same.
    The amount of genes present in Lily is 18 times more than the Human Genome.

    So, the correct option is '18times'.
  • Question 6
    1 / -0
    Which of the following is not an aim of human genome project?
  • Question 7
    1 / -0
    Which of the following is the largest gene in humans?
    Solution
    Dystrophin is a cytoplasmic rod-shaped protein consisting of which is chiefly situated in skeletal & cardiac muscles. Its formation includes the largest gene with 2.6 Mb and 97 exons.
    So, the correct answer is 'Dystrophin'
  • Question 8
    1 / -0
    Which of the following can improve the diagnosis of many genetic disorder?
  • Question 9
    1 / -0
    The human genome project is made up of .......... repetitive DNA sequences. 
    Solution
    • The Human Genome Project was an international effort to determine the DNA sequence of the entire Human Genome and the mapping of genes that are present in humans.
    • It is found that there are around 30000 to 40000 genes present in humans and 97% of the inactive DNA material contains around 50 percent of repetitive DNA material which makes around two-third of the sequence consisting of repetitive elements in humans.

    So, the correct option is '50%'.
  • Question 10
    1 / -0
    All of the following statements about DNA replication are true except 
    Solution
    A. Initiation of DNA synthesis always requires a smaller segment of RNA called RNA primer. It is synthesized by enzyme primase.
    B. The two strands of DNA  double helix unwind with the help of DNA unwinding protein, called helicase. The unwinding occurs as this protein begins its binding with DNA strands, thus, breaking the hydrogen bonds between complementary nitrogenous bases.
    C. DNA replication begins at certain fixed unique points and is called origin.
    D. The chromosomes of bacteria are circular. Bacterial DNA replication occurs in a bidirectional way and proceeds with two replication forks in a circular manner.
    E. Only one strand of DNA shows continuous replication which is called the leading strand. The other strand, called the lagging strand, replicates in a discontinuous manner by synthesizing short fragments called Okazaki fragments which are later joined by DNA ligase.
    Hence, statement C is incorrect. So, the correct answer is 'DNA replication begins at the promoter'.
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