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Haloalkanes and Haloarenes Test - 56

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Haloalkanes and Haloarenes Test - 56
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  • Question 1
    1 / -0
    Which of the following is the example of $$SN^2$$ reaction
    Solution
    Only $$1^\circ$$ alkyl halides, i.e. $$CH_3Br$$ undergoes $$S_{N}2$$ reaction. Lesser the bulkier group attached to the attacking carbon higher is its reactivity towards $$S_N2$$ reaction.
    Option A is correct.
  • Question 2
    1 / -0
    When ethyl chloride and alcoholic $$KOH$$ are heated , the compound obtained is
    Solution
    We know that
    $$CH_3CH_2Cl + KOH \rightarrow CH_2 = CH_2 + KCl + H_2O$$
    Thus in reaction ethene $$(C_2H_4)$$ is produced.
  • Question 3
    1 / -0
    The reaction
    $$CH_3CH=CH_3\xrightarrow[H^{+}]{CO+H_{2}O}CH_{3}-CH-CH_{3}$$
     
    $$COOH$$
     
    is known as
    Solution

  • Question 4
    1 / -0
    The reaction of benzene with chlorine in the presence of iron gives
    Solution
    The reaction between benzene and chlorine in the presence of either aluminium chloride or iron gives chlorobenzene.

  • Question 5
    1 / -0
    Ethylidine dichloride can be prepared by the reaction of $$HCl$$ and
    Solution
    Ethylidene chloride can be prepared by the reaction of HCl and acetylene$$C_2H_2$$.

  • Question 6
    1 / -0
    Which of the following is liquid at room temperature
    Solution
    $$CH_3F , CH_3Cl , CH_3Br$$ and $$C_2H_5Cl$$ are gases at room temperature. $$CH_3I$$ is a liquid at room temperature and solidifies at $$-66.5^\circ C.$$

    Option A is correct.
  • Question 7
    1 / -0
    When benzene is heated with chlorine in the presence of sunlight , it forms
    Solution
    When benzene is heated with chlorine in the presence of sunlight , it form benzene hexachloride.

  • Question 8
    1 / -0
    Which metal is used in Wurtz synthesis
    Solution
    $$CH_3Br + 2Na + Br - CH_3 \xrightarrow[Ether]{Dry} CH_3CH_3 + 2NaBr$$

    Sodium metal is used.
  • Question 9
    1 / -0
    Which  is formed when benzene is heated with chlorine in the presence of sunlight
    Solution
    The ring delocalisation is permanently broken and a chlorine or bromine atom adds on to each carbon atom. For example, if you bubble chlorine gas through hot benzene exposed to UV light for an hour, you get 1,2,3,4,5,6-hexachlorocyclohexane or benzenehexachloride.

  • Question 10
    1 / -0

    Directions For Questions

    In the following sequence of reactions, the products $$(A)$$ to $$(G)$$ are formed:

    ...view full instructions

    Compound $$(F)$$ is:
    Solution
    Compound $$(F)$$, answer is $$(d)$$

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