Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 18

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Weekly Quiz Competition

Question 1
1 / -0

The number of single and double bonds total present in ethanoic acid is -

A
5

B
6

C
7

D
8
Question 2
1 / -0

The secondary suffix, '-one' indicates the following functional group in the compound.

A
-COOH

B

C

D
- OH

Solution

Suffix" -one " is used for the ketone functional group. Therefore RCOR is the correct answer.
Question 3
1 / -0

IUPAC name of the compound $$CH_3-CH_2-\overset{\overset{O}{||}}C-CH_2-\overset{\overset{O}{||}}C-COOH$$ is:

A
hexanedione - 2, 4-ic-1-oic acid

B
2, 4- dioxohexanoic acid

C
propionyl-dioxo-oic acid

D
none of these

Solution

For naming the given compound ; $$H_{3}C-CH_{2}-CO-CH_{2}-CO-COOH$$, the following steps are followed:
i) The parent chain consists of six carbon atoms and the primary functional group is -COOH, thus the suffix -oic acid.
ii) The two secondary functional groups are -CO, thus the prefix -oxo is used for them.
iii) Numbering the compound is done from right to left, as lowest number is given to the -COOH group and also in accordance with the least sum rule for secondary functional groups.
Thus the name of the compound is 2,4-dioxohexanoic acid.
Question 4
1 / -0

$$O$$
$$||$$
$$X\xrightarrow[(ii)\,H_3O^{\oplus}]{(i)\, KMnO_4/H_2O/\Delta}HOOC - C-CH_2-CH_2-CH_2-CH_2-COOH$$.
$$X$$ is :

A

B

C

D

Solution

The acidified $$KMnO_4$$ solution oxidises the alkene by breaking the carbon-carbon double bond and replacing it with two carbon-oxygen double bonds. Under mild conditions, $$KMnO_4$$ can affect conversion of alkenes to glycols. That further oxidizes the glycol with cleavage of the carbon-carbon bond and forms acyclic dicarboxylic acid with substituted keto group.
Hence, X is represented by option A (Benzoic acid)
Question 5
1 / -0

IUPAC name of $$CH_3COOH$$ is:

A
acetic acid

B
formic acid

C
methanoic acid

D
ethanoic acid

Solution

It has 2 carbon atoms, and functional group is carboxylic group,suffix is "oic acid"
thus IUPAC name is Ethanoic acid
Question 6
1 / -0

The IUPAC name of carboxylic acid with three carbon atoms is:

A
ethanoic acid

B
acetic acid

C
propanoic acid

D
propionic acid

Solution

According to $$IUPAC$$ convention, acid group is given highest priority than saturated carbons. So the name would be propanoic acid since the number of carbons atom is three, a prefix is $$(propan-)$$
Question 7
1 / -0

In addition reactions of aldehydes, the carbonyl carbon atom changes from:

A
$$sp^{3}\ to\ sp^{2}$$

B
$$sp^{2}\ to\ sp^{3}$$

C
$$sp\ to\ sp^{3}$$

D
$$sp^{3}\ to\ sp$$

Solution

the carbonyl carbon atom has one $$\Pi$$ bond, thus one empty p-orbital, therefore $$sp^2$$ hybridisation.
on addition reaction $$\Pi$$ bond is lost and empty p-orbital is used up. Thus hybridisation is $$sp^3$$.
change is from $$sp^2$$ to $$sp^3$$.
Question 8
1 / -0

The IUPAC name of above structure is :

A
phenyl ethanone

B
methyl phenyl ketone

C
acetophenone

D
phenyl methyl ketone

Solution

The IUPAC name of given compound is phenyl ethanone. Its common name is acetophenone.

Alkyl aryl ketones are named as aryl alkanone.

Here, alkyl group is methyl group and aryl group is phenyl group.

Therefore, the option is A.
Question 9
1 / -0

$$\displaystyle CH_{3}CHO \xrightarrow[( ii )HCl\Delta ]{( i )Zn / Hg}$$
Write the product :

A
Methane

B
Ethane

C
Propane

D
Butane

Solution

Refer to image
Heating of carboxyl compound with finely divide, amalgamated zinc in a hydroxylic solvent containing a mineral acid such as $$HCl$$. The mercury alloyed with the zinc does not participate in the reaction it reverse only to provide a clean active metal surface.
Question 10
1 / -0

Cyanohydrin of which compound on hydrolysis will give lactic acid?

A
$$\displaystyle C_{6}H_{5}CHO$$

B
$$HCHO$$

C
$$\displaystyle CH_{3}CHO$$

D
$$\displaystyle CH_{3}CH_{2}CHO$$

Solution

The hydrolysis of acetaldehyde cyanohydrin gives lactic acid.