Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 36

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The IUPAC name of the compound is:

A
$$2$$-hydroxypropanoic acid

B
$$1$$-hydroxypropanoic acid

C
$$1$$-hydroxyehtane carboxylic acid

D
$$1$$-hydroxyethanoic acid

Solution

The IUPAC name of the following compound is $$2-$$ hydroxy propanoic acid.
Question 2
1 / -0

The IUPAC name of the compound is:

A
$$2$$-Methylbutan - $$3$$ - one

B
$$3$$-Methylbutan - $$2$$ - al

C
$$2$$-Methylbutan - $$3$$ - al

D
$$3$$-Methylbutan - $$2$$ - one

Solution
Question 3
1 / -0

The IUPAC name of $$NC - CH_2 - CH_2 - COOH$$ is:

A
$$3$$- carboxy propanenitrile

B
$$4$$- cyanobutanoic acid

C
$$2$$- cyanomethane Carboxylic acid

D
$$3$$- cyanopropanoic acid

Solution

The IUPAC name of the following compound is $$3$$- cyanopropanoic acid.
Question 4
1 / -0

Arrange the following compounds in correct order of acidic strength.

A
$$HCOOH>CH_3COOH>C_6H_5OH>C_2H_5-OH$$

B
$${ CH }_{ 3 }COOH>HCOOH>C_6H_5OH>C_2H_5-OH$$

C
$${ C }_{ 6 }{ H }_{ 5 }{ OH }>HCOOH>CH_3COOH>C_2H_5-OH$$

D
None of these

Solution

The correct increasing order of acidic strength is given by $${ C }_{ 2 }{ H }_{ 5 }OH<{ C }_{ 6 }{ H }_{ 5 }OH<{ CH }_{ 3 }{ CO }_{ 2 }H<{ HCO }_{ 2 }H$$. When substituent group is electron releasing, then the acidity decreases. Hence $${ CH }_{ 3 }{ CO }_{ 2 }H$$ is less acidic than $${ HCO }_{ 2 }H$$.
As both $${ C }_{ 2 }{ H }_{ 5 }OH$$ & $${ C }_{ 2 }{ H }_{ 5 }OH$$ come under alcohols $${ C }_{ 2 }{ H }_{ 5 }OH$$ is acidic acid due to resonance stabilized $${ C }_{ 6 }{ H }_{ 5 }{ O }^{ - }$$ ion.
Question 5
1 / -0

The correct name of the given compound :
$${ CH }_{ 3 }-\overset { \underset { | }{ H } }{ \underset { \overset { | }{ OH } }{ C } } -{ COOH }$$

A
glycoxal

B
lactic acid

C
glycine

D
glyceraldehyde

Solution

The given compound is Lactic acid.
It contain one $$-OH$$ group and one $$-COOH$$ group along with 3 carbon atoms.
Question 6
1 / -0

Which of the following carboxylic acids undergoes decarboxylation most easily on heating?

A
$$CH_3CH_2COOH$$

B

C

D

Solution

(C) i.e $$CH_3-CO-CH_2-COOH$$ will go fastest decarboxylation as it is a $$\beta-$$ keto acid.
$$\beta-$$ keto acid on slight heating decarboxylates and gives ketone.
Question 7
1 / -0

What is the name of this following compound?
$$CH_3CH_2COCl$$

A
Butanoyl chloride

B
Propanoyl chloride

C
1 chloro propanone

D
None of these

Solution

$$\overset {3}CH_3\overset {2}CH_2\overset {1}COCl$$

This is an acid chloride. In the IUPAC name the suffix "$$\text{oyl chloride}$$" is added.

The number of carbon atoms in the chain is $$3$$. The name will be $$\text{propanoyl chloride}$$ .

Therefore, the correct option is B.
Question 8
1 / -0

An organic compound, $$C_3H_8O$$ does not give a precipitate with $$2,4$$-dinitrophenyl hydrazine reagent and does not react with metallic sodium. It could be:

A
$$CH_3-CH_2-CHO$$

B
$$CH_2=CH-CH_2OH$$

C
$$CH_3-O-CH_3$$

D
$$CH_2=CH-O-CH_3$$

Solution

Since aldehyde only reacts with $$2,4$$ dinitro phenyl hydrazine, so given compound is not aldehyde. To react with metallic sodium which is base, acidic group is required like $$-OH, -COOH,$$ etc . Hence compound is $$CH_2=CH-O-CH_3$$
Question 9
1 / -0

Carbonyl group is converted into methylene group by?

A
Acidic reduction

B
Raney Ni

C
Basic hydrolysis

D
Normal Hydrogenation

Solution

It is basically reduction reaction where $$ -\underset{|}C=O$$ bond is reduced to $$ -\underset{|}CH_2 $$ bond using $$Zn(Mg) + conc.HC$$ which is acidic reduction.
Acid increases electrophilicity of carbonyl carbon by oxygen protonation.
Question 10
1 / -0

The most possible product is:

A

B

C

D

Solution

Grignard reagent is hard base so it does not undergo $$1,4$$ addition at soft centres, it only reacts to $$1,2$$ centres.