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Biomolecules Test - 56

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Biomolecules Test - 56
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  • Question 1
    1 / -0
    A peptide hormone is:
    Solution
    Insulin is a peptide hormone produced by beta cells of the pancreatic islets.

    It is considered to be the main anabolic hormone of the body. Insulin contains two polypeptide chains with 21 and 30 amino acids which are joined together by sulphur bridges. Hence, it is a peptide hormone.
  • Question 2
    1 / -0
    The presence or absence of hydroxyl group on which carbon atom of sugar differentiates RNA and DNA ?
    Solution
    Ribose contains -OH at $$C_2$$ but deoxyribose dos not.

  • Question 3
    1 / -0
    Intermediate common to fatty acid and carbohydrate oxidation is ______________.
    Solution
    B. Acetyl CoA
    Solution: The oxidation of fatty acid and carbohydrate ultimately forms ATP. The common intermediate in all these oxidation is Acetyl CoA. SAcetyl CoA is snthesized in mitochondria by a number of reactions: oxidative decarboxylation of pyruvate, beta oxidation of fatty acids.
    So the correct answer is "Acetyl CoA".

  • Question 4
    1 / -0
    Which of the following hexoses will form the same osazone when treated with excess phenyl hydrazine?
    Solution
    D-glucose, D-fructose, and D-mannose form the same osazone when treated with an excess of phenylhydrazine because they differ only in the configuration of 1st and 2nd carbon atoms which are transformed to the same form. 

  • Question 5
    1 / -0
    Which of the following is the correct statement ?
    Solution
    Starch is also known as amylum which occurs in all green plants. A molecule of starch $$(C_6H_{10}O_5)$$ is built of a large number of $$\alpha$$-glucose ring joined through oxygen-atom.

    Hence,option A is correct.
  • Question 6
    1 / -0
    $${Q}_{10}$$ value for enzyme is generally found to be____________.
  • Question 7
    1 / -0
    The number of moles of substrate converted per minute by one mole of enzyme is called.
    Solution
    Turnover number is defined as the number of substrate molecules transformed per minute by a single enzyme molecule when the enzyme is the rate-limiting factor. he higher the turn over number, the more efficient an enzyme. It depends upon all the active points present over enzymes.
    So, the correct option is 'A'.
  • Question 8
    1 / -0
    Consider the following statements about enzymes.
    a. Most enzymes are proteinaceous, although some are RNA molecules
    b. The specificity of an enzyme is due to its well-defined three dimensional structure and the active site present in it.
    c. Prosthetic group is loosely bound to the apoenzyme part of the enzyme.
    d. Portions, prosthetic group and apoenzyme are enzymatically inactive when separated from each other.
    Pick the correct ones from these statements.
  • Question 9
    1 / -0
    A $$25,000$$ Da protein contains a single binding site for a molecule(ligand), whose molecular weight is $$2,500$$Da. Assuming high affinity and physiologically irreversible binding, the amount of the liquid required to occupy all the binding sites in $$10$$mg protein will be
    Solution
    It is given that 25,000 Da protein contains single binding site for ligand with molecular weight 2,500 Da. 
    Hence, 10 mg of protein will require approximately 10 x 2,500 / 25, 000 = 1 mg of ligand to occupy all the binding sites in protein.
    Thus, the correct answer is option B.
  • Question 10
    1 / -0
    Enzymes play an essential role in the body because ________.
    Solution
    Enzymes are biological catalysts. Catalysts are substances that increase the rate of chemical reactions without being used up. Thus the correct answer is option D. 
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