Biomolecules Test

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Biomolecules Test - 62

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Weekly Quiz Competition

Question 1
1 / -0

Which among the following is not the example of carbohydrate ?

A
Glucose

B
fractose

C
Maltose

D
Nylon

Solution

$$\rightarrow$$ Carbohydrates are important source of instant energy in our body system.
$$\rightarrow$$ Honey has been used as instant source of enrgy in ayurvedic medicines.
$$\rightarrow$$ Carbohydrates are used as storage starch in plants and glycogen
$$\rightarrow$$ carbohydrates are also used in textile industry.
So, the correct answer is NYLON (It is a synthetic polymer)
Question 2
1 / -0

Glucose phosphates formed in photosynthesis are Asymmetrically labeled it is called:

A
Warbug's effect

B
Pasteur's effect

C
Dicken's effect

D
Gibb's effect

Solution

Glucose phosphates formed in the photosynthesis are Asymmetrically labeled it is called Gibb's Effect.
Question 3
1 / -0

When an apoenzyme is separated from its metal component, its activity is

A
Decreased

B
Increased

C
Lost

D
Not affected

Solution

Enzymes are high molecular protein molecules, conjugated with non-protein cofactors i.e apoenzyme which is composed of amino acids only and a prosthetic group consist of a non- protein groups. Cofactors are mostly metal ions or coenzymes, the binding of the enzyme to a coenzyme forms a holoenzyme which has the necessary components for the proper functioning of an active enzyme, separation causes decreased in catalytic activity.
So, the correct answer is 'decreased'.
Question 4
1 / -0

The tightly bound non proteinaceous organic compound is?

A
Prosthetic group

B
Cofactor

C
Apoenzyme

D
Holoenzyme

Solution

A cofactor is a non-protein chemical compound or metallic ion that is required for an enzyme's activity. Cofactors can be subclassified as either inorganic ions or complex organic molecules called coenzymes, the latter of which is mostly derived from vitamins and other organic essential nutrients in small amounts. A coenzyme that is tightly or even covalently bound is termed a prosthetic group.

So the correct option is 'Prosthetic group'.
Question 5
1 / -0

Which of the following method/s is/are used in N-terminal amino acid and residue analysis ?

A
Using 2, 4-dinitrofluorobenzene is mildly basic solution

B
Labeling the reaction between the N-terminal amino group and phenyl isothiocyanate

C
Use of carboxy peptidases

D
Partial hydrolysis method

Solution
Question 6
1 / -0

For 'invert sugar', the correct statement(s) is (are)
(Given : specific rotations of (+) -sucrose, (+) -maltose, L-(-)-glucose and L-(+)-fructose in aqueous solution are $$+66^0, +140^0, -52^0$$ and $$92^0$$, respectively)

A
'invert sugar' is prepared by acid catalyzed hydrolysis of maltose

B
'invert sugar' is an eqimolar mixture of D-(+)-glucose and D-(-)-fructose

C
specific rotation of 'invert sugar' is $$-20^0$$

D
on reaction with $$Br_2$$ water, 'invert sugar' forms saccharic acid as one of the products

Solution

Invert sugar is a sucrose, partially or totally cleaved into fructose and glucose. Sucrose is converted into invert sugar by chemical reaction called hydrolysis by heating a mixture or solution of table sugar.
Also, breakdown of sucrose may happen in a reaction catalyzed by enzymes such as sucrose, invertase etc or by acid catalyzed hydrolysis of maltose.
Question 7
1 / -0

The reagent which may be used to distinguish between cane sugar and glucose solution is

A
Molusch's reagent

B
Iodine solution

C
Baeyer's reagent

D
Fehling's solution

Solution
Question 8
1 / -0

One mole of each of glucose and fructose require $$x$$ and $$y$$ moles of periodic acid respectively, for oxidation. Hence, $$x/y$$ is

A
$$1/1$$

B
$$2/1$$

C
$$5/4$$

D
$$9/4$$

Solution
Question 9
1 / -0

The $$\alpha$$- D glucose and $$\beta$$- D glucose differ from each other due to difference in carbon atom with respect to its

A
Number of $$OH$$ groups

B
Size of hemiacetal ring

C
Conformation

D
Configuration

Solution
Question 10
1 / -0

Molisch test is answered by

A
All carbohydrates

B
Sucrose

C

Fructose

D

Glucose

Solution

Molisch test is a test for carbohydrate or compounds which can be dehydrated to furfural or furfural derivatives in the presence of the concentrated sulphuric acid .

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Re-Attempt Weekly Quiz Competition

Biomolecules Test - 62

Result

Biomolecules Test - 62

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Rank

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SHARING IS CARING

Question 1

Glucose

fractose

Maltose

Nylon

Solution

Question 2

Warbug's effect

Pasteur's effect

Dicken's effect

Gibb's effect

Solution

Question 3

Decreased

Increased

Lost

Not affected

Solution

Question 4

Prosthetic group

Cofactor

Apoenzyme

Holoenzyme

Solution

Question 5

Using 2, 4-dinitrofluorobenzene is mildly basic solution

Labeling the reaction between the N-terminal amino group and phenyl isothiocyanate

Use of carboxy peptidases

Partial hydrolysis method

Solution

Question 6

'invert sugar' is prepared by acid catalyzed hydrolysis of maltose

'invert sugar' is an eqimolar mixture of D-(+)-glucose and D-(-)-fructose

specific rotation of 'invert sugar' is $$-20^0$$

on reaction with $$Br_2$$ water, 'invert sugar' forms saccharic acid as one of the products

Solution

Question 7

Molusch's reagent

Iodine solution

Baeyer's reagent

Fehling's solution

Solution

Question 8

$$1/1$$

$$2/1$$

$$5/4$$

$$9/4$$

Solution

Question 9

Number of $$OH$$ groups

Size of hemiacetal ring

Conformation

Configuration

Solution

Question 10

All carbohydrates

Sucrose

Fructose

Glucose

Solution

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