General Principles and Processes of Isolation of Elements Test

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General Principles and Processes of Isolation of Elements Test - 43

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Weekly Quiz Competition

Question 1
1 / -0

Match the column I with column II and mark the appropriate choice.
Column I Column II
(A) Van Arkel (i) $$Ni$$
(B) Zone refining (ii) $$Ti$$
(C) Mond process (iii) $$Ag$$
(D) Cupellation (iv) $$Ge$$

A
(A) $$\rightarrow$$(i), (B)$$\rightarrow$$(ii), (C)$$\rightarrow$$(iii), (D) $$\rightarrow$$ (iv)

B
(A) $$\rightarrow$$(iii), (B)$$\rightarrow$$(i), (C)$$\rightarrow$$(ii), (D) $$\rightarrow$$ (iv)

C
(A) $$\rightarrow$$(ii), (B)$$\rightarrow$$(iv), (C)$$\rightarrow$$(i), (D) $$\rightarrow$$ (iii)

D
(A) $$\rightarrow$$(iv), (B)$$\rightarrow$$(iii), (C)$$\rightarrow$$(i), (D) $$\rightarrow$$ (ii)

Solution

Van Arkel process for refining $$Zr, Ti$$.
Zone refining for semiconductor like $$Ge$$.
Mond process for refining $$Ni$$.
Cupellation for refining noble metals like $$Ag, Au$$.
Question 2
1 / -0

Zone refining is based on the principle that________.

A
impurities of low boiling metals can be separated by distillation

B
impurities are more soluble in molten metal than in solid metal

C
different component of a mixture are differently adsorbed on an adsorbent

D
vapours of volatile compound can be decomposed in pure metal

Solution

Zone refining is based on the difference in solubility of impurities in molten and solid state of the metal. Semi conductors like $$Si,Ge$$ and $$Ga$$ are purified by this method.
Question 3
1 / -0

The method of zone refining of metals is based on the principle of:

A
greater mobility of pure metal than that of impurity.

B
higher melting point of the impurity than that of pure metal

C
all above are correct

D
greater solubility of the impurity in the molten state than in the solid.

Solution

Zone refining is based on the difference in solubility of impurities in molten and solid state of the metal. Semiconductor like $$Si,Ge$$ and $$Ga$$ are purified by this method.
Question 4
1 / -0

What is the main composition of matte?

A
$$CuS$$

B
$$CuO$$

C
$$Cu_{2}S$$

D
$$Cu_{2}O$$

Solution

Copper matte is a combination of copper sulphide and a small amount of iron sulphide. In the process of copper extraction matte is the stage subsequent to the final reduction process which involves converting it to crude copper.
The composition of copper in copper matte is:
Copper sulphide $$Cu_2S$$, $$80-95$$%
Question 5
1 / -0

The method of zone refining of metals is based on the principal of:

A
Greater mobility of the pure metal than that of the impurity

B
Higher melting point of the impurity than that of the pure metal

C
Greater noble character of the solid metal than that of the impurity

D
Greater solubility of the impurity in the molten state than in the solid

Solution

Zone refining is based on the difference in solubility of impurities in molten and solid-state of the metal. Semi-conductor like $$Si, Ge$$ and $$Ga$$ are purified by this method.

Hence, the correct option is $$D$$
Question 6
1 / -0

In case of Hall's process applied on reduction of $$Al_2O_3$$ to Al can be done by using:

A
Cathode - Al, Anode - Graphite

B
Cathode - Graphite, Anode - Graphite

C
Cathode - Graphite, Anode - Steel

D
Cathode - Steel, Anode - Graphite

Solution

Both are graphite
since in Hall's Process both the terminals are carbon content.
Question 7
1 / -0

Which of the following compound is used as froth stabliser?

A
Fatty acid

B
Aniline

C
Xanthates

D
Phosphoric acid

Solution

Here answer is option B
Aniline stabilize the froth before it is taken out for further treatment.
In this process, a suspension of a powdered ore is made with water. In this process, a suspension of a powdered ore is made with water. Collectors like pine oil, fatty acids and xanthates are added to it. Froth stabilizer like cresols, aniline stabilize the forth
Question 8
1 / -0

The mass of carbon anode consumed (giving of carbon dioxide) in the production of $$270 \ kg$$ aluminium metal bum bauxite by Hall process is: (Atomic mass $$Al = 27$$)

A
$$180$$ kg

B
$$270$$ kg

C
$$540$$ kg

D
$$90$$ kg

Solution

The chemical reaction for the Hall process is given by
$$2Al_2O_3+3C\rightarrow 4Al+3CO_2$$
Moles of aluminium produced$$=\dfrac{270000}{27}=10000$$
According to the reaction,
$$10000 \; kg$$ moles of aluminium can be produced by consuming $$2500\times3=7500 \ moles $$ of Carbon
Hence mass of carbon=$$12\times 7500=90000\ g=90\ kg$$

Therefore, D is the correct answer
Question 9
1 / -0

Identify the oxide ore among the following :

A
Copper pyrites

B
Copper glance

C
Siderite

D
Limonite

Solution

Formula of Limonite is $$F_eO(OH)\cdot nH_2O$$. It is an oxide ore.
Question 10
1 / -0

Aluminothermy used for the spot welding of large iron structure is based on the fact that-

A
reaction between iron and oxygen is endothermic

B
as compared to to Al, Fe has greater affinity for oxygen

C
as compared to iron, Al has great affinity for oxygen

D
reaction between Al and oxygen is endothermic

Solution

Solution:- (C) as compared to iron, $$Al$$ has great affinity for oxygen
Since $$Al$$ is more electropositive and has greater affinity for oxygen than iron.
This fact has made the use of aluminothermy in welding of large iron structure.

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Re-Attempt Weekly Quiz Competition

	Column I		Column II
(A)	Van Arkel	(i)	$$Ni$$
(B)	Zone refining	(ii)	$$Ti$$
(C)	Mond process	(iii)	$$Ag$$
(D)	Cupellation	(iv)	$$Ge$$

General Principles and Processes of Isolation of Elements Test - 43

Result

General Principles and Processes of Isolation of Elements Test - 43

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Question 1

(A) $$\rightarrow$$(i), (B)$$\rightarrow$$(ii), (C)$$\rightarrow$$(iii), (D) $$\rightarrow$$ (iv)

(A) $$\rightarrow$$(iii), (B)$$\rightarrow$$(i), (C)$$\rightarrow$$(ii), (D) $$\rightarrow$$ (iv)

(A) $$\rightarrow$$(ii), (B)$$\rightarrow$$(iv), (C)$$\rightarrow$$(i), (D) $$\rightarrow$$ (iii)

(A) $$\rightarrow$$(iv), (B)$$\rightarrow$$(iii), (C)$$\rightarrow$$(i), (D) $$\rightarrow$$ (ii)

Solution

Question 2

impurities of low boiling metals can be separated by distillation

impurities are more soluble in molten metal than in solid metal

different component of a mixture are differently adsorbed on an adsorbent

vapours of volatile compound can be decomposed in pure metal

Solution

Question 3

greater mobility of pure metal than that of impurity.

higher melting point of the impurity than that of pure metal

all above are correct

greater solubility of the impurity in the molten state than in the solid.

Solution

Question 4

$$CuS$$

$$CuO$$

$$Cu_{2}S$$

$$Cu_{2}O$$

Solution

Question 5

Greater mobility of the pure metal than that of the impurity

Higher melting point of the impurity than that of the pure metal

Greater noble character of the solid metal than that of the impurity

Greater solubility of the impurity in the molten state than in the solid

Solution

Question 6

Cathode - Al, Anode - Graphite

Cathode - Graphite, Anode - Graphite

Cathode - Graphite, Anode - Steel

Cathode - Steel, Anode - Graphite

Solution

Question 7

Fatty acid

Aniline

Xanthates

Phosphoric acid

Solution

Question 8

$$180$$ kg

$$270$$ kg

$$540$$ kg

$$90$$ kg

Solution

Question 9

Copper pyrites

Copper glance

Siderite

Limonite

Solution

Question 10

reaction between iron and oxygen is endothermic

as compared to to Al, Fe has greater affinity for oxygen

as compared to iron, Al has great affinity for oxygen

reaction between Al and oxygen is endothermic

Solution

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