Coordination Compounds Test

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Coordination Compounds Test - 61

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Weekly Quiz Competition

Question 1
1 / -0

The incorrect statement about compound mercury tetrathiocyanatocobaltate(III)

A
It cannot show structure isomerism

B
Compound is octaherdral

C
The formula of compound is $$Hg[Co(SCN)_4]$$

D
Coordination number of $$Co$$ is $$4$$
Question 2
1 / -0

A complex of iron and cynide is $$100 \%$$ ionised at $$1 m$$ if its elevation in boiling point is $$2.08^{o}$$ ($${K_b}=0.52^{o}mol/kg$$) then the complex is:

A
$${K_3}[{Fe(C{N)_6}}]$$

B
$$Fe{(CN)_2}$$

C
$${K_4}[{Fe(C{N)_6}}]$$

D
$$Fe{(CN)_4}$$

Solution
Question 3
1 / -0

Select the correct statement(s) about "Ziese's salt'', $$K[PtCl_{3}(\eta^ {2}-C_{2}H_{4})]$$.

A
It has only two types of $$M-Cl$$ bond length

B
$$E.A.N=84$$

C
It is a $$\pi-$$bonded organometallic compound

D
All of these
Question 4
1 / -0

Number of ions present in $$K_{4}[Fe(CN)_{6}]$$

A
$$2$$

B
$$10$$

C
$$3$$

D
$$5$$

Solution
Question 5
1 / -0

In the following reaction the major complex product is $$[PtCl_{4}]^{2-}+2NH_{3}\rightarrow\ [PtCl_{2}(NH_{3})_{2}]+2Cl^{-}$$

A
cis

B
trans

C
anyone

D
can't be predicted
Question 6
1 / -0

The total number of possible isomers for the square planar $$[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$$ is :

A
$$12$$

B
$$8$$

C
$$16$$

D
$$24$$
Question 7
1 / -0

The primary valency of iron in $${{\text{K}}_{\text{4}}}\left[ {{\text{Fe}}{{\left( {{\text{CN}}} \right)}_{\text{6}}}} \right]$$ is

A
1

B
2

C
3

D
4

Solution
Question 8
1 / -0

Consider the following two complex ions: $${[Co{F}_{6}]}^{3-}$$ and $${ \left[ Co{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ 3 } \right] }^{ 3- }$$. Which of the following statement(s) is/are false?

A
Both are octahedral

B
$${ \left[ Co{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ 3 } \right] }^{ 3- }$$ is diamagnetic while $${[Co{F}_{6}]}^{3-}$$ is paramagnetic

C
Both are outer orbitals complexes

D
In both the complexes, the central metal is in the same oxidation state
Question 9
1 / -0

Which is the following complex shown optical activity?

A
$$trans-\left[ CO\left( ox \right) _{ 2 }{ Cl }_{ 2 } \right] ^{ 3- }$$

B
$$\left[ CO\left( NH_{ 3 } \right) _{ 3 }{ Cl }_{ 3 } \right] $$

C
$$\left[ Fe\left( edta \right) \right] ^{ \_ }$$

D
$$cis-\left[ Pt\left( NH_{ 3 } \right) _{ 2 }{ Cl }_{ 2 } \right] $$
Question 10
1 / -0

Which of the following statement is wrong:

A
Hybridisation is the mixing of atomic orbitals prior to their combining into molecular orbitals

B
$$sp^2$$ hybrid orbital are formed from two p atomic orbitals and one s atomic orbital

C
$$dsp^2$$ hybrid orbitals are all at $$90^o$$ to one another

D
$$sp^3d^2$$ hybrid orbitals are directed towards the corners of a regular tetrahedron

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Re-Attempt Weekly Quiz Competition

Coordination Compounds Test - 61

Result

Coordination Compounds Test - 61

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SHARING IS CARING

Question 1

It cannot show structure isomerism

Compound is octaherdral

The formula of compound is $$Hg[Co(SCN)_4]$$

Coordination number of $$Co$$ is $$4$$

Question 2

$${K_3}[{Fe(C{N)_6}}]$$

$$Fe{(CN)_2}$$

$${K_4}[{Fe(C{N)_6}}]$$

$$Fe{(CN)_4}$$

Solution

Question 3

It has only two types of $$M-Cl$$ bond length

$$E.A.N=84$$

It is a $$\pi-$$bonded organometallic compound

All of these

Question 4

$$2$$

$$10$$

$$3$$

$$5$$

Solution

Question 5

cis

trans

anyone

can't be predicted

Question 6

$$12$$

$$8$$

$$16$$

$$24$$

Question 7

1

2

3

4

Solution

Question 8

Both are octahedral

$${ \left[ Co{ \left( { C }_{ 2 }{ O }_{ 4 } \right) }_{ 3 } \right] }^{ 3- }$$ is diamagnetic while $${[Co{F}_{6}]}^{3-}$$ is paramagnetic

Both are outer orbitals complexes

In both the complexes, the central metal is in the same oxidation state

Question 9

$$trans-\left[ CO\left( ox \right) _{ 2 }{ Cl }_{ 2 } \right] ^{ 3- }$$

$$\left[ CO\left( NH_{ 3 } \right) _{ 3 }{ Cl }_{ 3 } \right] $$

$$\left[ Fe\left( edta \right) \right] ^{ \_ }$$

$$cis-\left[ Pt\left( NH_{ 3 } \right) _{ 2 }{ Cl }_{ 2 } \right] $$

Question 10

Hybridisation is the mixing of atomic orbitals prior to their combining into molecular orbitals

$$sp^2$$ hybrid orbital are formed from two p atomic orbitals and one s atomic orbital

$$dsp^2$$ hybrid orbitals are all at $$90^o$$ to one another

$$sp^3d^2$$ hybrid orbitals are directed towards the corners of a regular tetrahedron

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