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Coordination Co...

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  • Question 1
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    Which among the following is used in the treatment of cancer?

  • Question 2
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    A molecule $$(X)$$ has (i) four sigma bonds formed by the overlap of $$sp^{2}$$ and $$s$$ orbitals; (ii) one sigma bond formed by $$sp^{2}$$ and $$sp^{2}$$ - orbitals and (iii) one $$\pi-bond$$ formed by $$p_{z}$$ and $$p_{z}$$ orbitals. Which of the following is $$X$$?

  • Question 3
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    The total number of possible coordination isomer for the given compound $$[Pt(NH_3)_4Cl_2][PtCl_4]$$ is?

  • Question 4
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    The octahedral complex $$CoSO_4Cl_5\,NH_3$$ exists in two isomeric forms $$X$$ and $$Y$$. Isomers $$X$$ reacts with $$AgNO_3$$ to give a white precipitate, but does not react with $$BaCl_2$$. Isomer $$Y$$ gives white precipitate with $$BaCl_2$$ but does not react with $$AgNO_3$$.
    Isomers $$X$$ and $$Y$$ are: 

  • Question 5
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    Brown ring complex known as:

  • Question 6
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    Which complex among the following gives a white precipitate on treatment with an aqueous solution of barium chloride?

  • Question 7
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    The complexes $$[Cr(NH_3)_6][Co(CN)_6]$$ and $$[Co(NH_3)_6][Cr(CN)_6]$$ are not the example of?

  • Question 8
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    Directions For Questions

    A metal complex having composition $$Cr(NH_3)_4Cl_2Br$$ has been isolated in two forms, (X) and (Y). The form (X) reacts with $$AgNO_3$$ to give a white precipitate readily soluble in dilute aqueous ammonia, whereas (Y) gives a pale yellow precipitate soluble in concentrate ammonia.

    ...view full instructions

    Choose the correct statement regarding the complexes X and Y:
    (I) Both complexes have the same six geometrical isomer.
    (II) Both complexes have nearly the same conductivity in $$H_2O$$.
    (III) In both complexes, $$NH_3$$ is involved only to secondary valency.
    (IV) In both complexes, electronic configuration of $$t_{2g}$$ is same.

  • Question 9
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    Directions For Questions

    Hybridization is the measure to express the molecular shapes reasonably. Hybridization, although theoretical, but is highly correlated with molecular shapes or inter orbital angles. If there is any departure in geometry in apparent departure in hybridization can be observed and the following characteristic relationship is the easiest way to interpret that departure. Any hybrid orbital made by s and p-orbitals is characterized by the following relationship.

       $$ f_s = \dfrac {1}{i + 1}$$ or $$f_p = \dfrac {i}{i+1}$$ and $$i =\dfrac {f_p}{f_s} $$

    For $$ sp^3, i= 3$$ and $$sp^2, i=2 $$ for an orbital, $$ f_s + f_p = 1 $$ while all the s-p hybrids of gein atom must satisfy the condition.

      $$ \sum { f_x} = 1.00 $$

    d and the inter orbital angle between two equivalent (  same $$f_s$$ and same $$f_p$$ )  hybrid orbitals is given by 

       $$ cos \theta = \dfrac {-1}{i} $$

    ...view full instructions

    VSEPR theory suggest a small departure from $$ 109^0 28'$$ for $$ NH_3 $$ molecule. The H-N-H bond angle has been found to be $$ 107^0 $$ what kind of hybrid orbital will be occupied by the non -bonding pair of electron?

  • Question 10
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    Match the complex species given in Column-I with the possible isomerism given in Column-II and assign the correct code.

    Column-I(Complex species)Column-II(Isomerism)
    (a) $$[Co(NH_3)_4Cl_2]^+$$(p) Optical
    (b) cis-$$[Co(en)_2Cl_2]^+$$(q) Ionization
    (c) $$[Co(NH_3)_5(NO_2)]Cl_2$$(r) Coordination
    (d) $$[Co(NH_3)_6][Cr(CN)_6]$$(s) Geometrical
    (t) Linkage

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