Relations and Functions Test

Result

Relations and Functions Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is an even function?

A
sin³x

B
tan⁵x

C
x²+ sin² x

D
√x

Solution

Because, f(-x) = f(x) is the necessary condition for a function to be an even function, which is only satisfied by x²+ sin²x.
Question 2
1 / -0

The domain of the function f(x) = √x−1 + √6−x is

A
[0, ∞)

B
(1,6)

C
[1,6]

D
[0,6]

Solution

x-1 ≥ 0 and 6 – x ≥ 0 ⇒ 1 ≤ x ≤ 6.
Question 3
1 / -0

The function f(x) = sin x²is

A
signum function

B
Greatest integer function

C
an even function

D
Odd function

Solution

For even function : f(-x) = f(x), therefore, f( − x) = sin (− x)²= sin x²= f(x).