Matrices Test -...

lf $$\mathrm{A}=\left\{\begin{array}{lll}
1 & 1 & 3\\
5 & 2 & 6\\
-2 & -1 & -3
\end{array}\right\},$$ then $$\mathrm{A}^{3}$$ is a/an

$$A=\begin{bmatrix} 2 & 2 & 2 \\ 2 & 2 & 2 \\ 2 & 2 & 2 \end{bmatrix}$$ then $$A^{3}-35A=$$

Let $$\left[\begin{array}{ll}
2 & -2\\-2 & \ 5
\end{array}\right]=\left[\begin{array}{ll}
1 & 0\\
-1 & 1
\end{array}\right]\left[\begin{array}{ll}
2 & 0\\
0 & x
\end{array}\right]\left[\begin{array}{ll}
1 & -1\\
0 & 1
\end{array}\right]$$, then the value of $$x$$ is

If $$A=\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$$, then additive inverse of A is

If A and B are two matrices such that $$AB = B$$ and $$BA = A$$, then $$A^2 + B^2$$ is equal to

If $$A \times \begin{bmatrix} 1 & 1\\ 0 & 2 \end{bmatrix} = [1 \ \ 2],$$ then A =

$$\begin{bmatrix}a\ \
b\end{bmatrix}$$ x $$\begin{bmatrix}x\\y \end{bmatrix} =$$           

If $$A = \begin{bmatrix} 1 & -1\\ 2 & -1 \end{bmatrix}; B = \begin{bmatrix} 1 & 1\\ 4 & -1 \end{bmatrix},$$ then $$A^2 + B^2 =$$

Multiplication of two matrices $$A$$ and $$ B$$ i.e. $$AB,$$ is possible if and only if

If $$P=\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}$$ and if
$$PQ=\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$$,then $$Q=$$