Integrals Test ...

$$\displaystyle \int_{0}^{16}\frac{dx}{\sqrt{x+9}-\sqrt{x}}=$$

$$\displaystyle \int_{0}^{1}\frac{\sqrt{x}}{1+x}dx_{=}$$

$$\displaystyle \int_{0}^{\pi/4}\frac{\sqrt{\tan x}}{sin x cos x}dx=$$

$$\displaystyle \int_{1}^{2}\frac{dx}{x^{2}-2x+4}=$$

$$\displaystyle \int_{0}^{1}\frac{x}{1+\sqrt{x}}dx_{=}$$

$$\displaystyle \int_{0}^{\pi}\frac{dx}{3+2\sin x+\cos x}=$$

The value of $$\displaystyle \int_{0}^{\pi /4}\displaystyle \frac{\sin^{ \frac{1}{2}}x}{\cos^{ \frac{5}{2}}x} dx$$ is

$$\displaystyle \int_{0}^{\pi/2}(2\tan\frac{x}{2}+x\sec^{2}\frac{x}{2})dx=$$

$$\int_{2}^{3}\dfrac{2-x}{\sqrt{5x-6-x^{2}}} dx =$$