Application of ...

Area of the region $$\{(x,y)/x^{2}+y^{2}\leq 1\leq x+y\}$$ is:

The area bounded by the curves $$y=\cos x,y=\cos 2x$$ between the ordinates $$x=0,x=\displaystyle \frac{\pi}{3}$$ are in the ratio

The area bounded by $$y^{2}=4ax$$ and $$y=mx$$ is $$\displaystyle \frac{a^{2}}{3}$$ sq. units then $$\mathrm{m}$$

Area of the segment cut off from the parabola $$x^{2}=8y$$ by the line $$x-2y+8=0$$ is:

The area bounded by $$y=3x$$ and $$y=x^{2}$$ is (in square units)

The area bounded by the two curves $$y=\sin x,\ y=\cos x$$ and the $$\mathrm{X}$$-axis in the first quadrant $$\left[0,\displaystyle \frac{\pi}{2}\right]$$ is

Area bounded by $$y=\sqrt{a^{2}-x^{2}},\ x+y=0$$ and $$\mathrm{y}$$-axis in sq. units is:

Area ofthe region bounded by $$y=|x|$$ and $$\mathrm{y}=2$$ is 

The area of a region bounded by $$\mathrm{X}$$-axis and the curves defined by $$y=\tan x ,  0\displaystyle \leq x\leq\frac{\pi}{4}$$ and $$y=\displaystyle \cot x,\frac{\pi}{4}\leq x\leq\frac{\pi}{2}$$ is:

The area bounded by $$y=\cos x,\ y=x+1$$ and $$y=0$$ in the second quadrant is