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Application of Integrals Test - 70

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Application of Integrals Test - 70
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The area of the region bounded by the curve
    $$x={ y }^{ 2 }-2\quad and\quad x=y\quad is$$
    Solution

  • Question 2
    1 / -0
    The area bounded by the curve $$y=\begin{cases} x^{ 2 };x<0 \\ x;x\ge 0 \end{cases}$$ and the line $$y=4$$ is 
    Solution

  • Question 3
    1 / -0
     The area enclosed between the curve $${x^2} + {y^2} = 16$$ and the coordinates axes in the first quadrant is 
    Solution

  • Question 4
    1 / -0
    y= f(x) is a function which satisfies -
    (i)f(0)=0          (ii)f''(x)= f'(x) and         (iii) f'(0)=1
    then the area bounded by the graph of y = f(x), the lines x=0,x-1=0 and y+1=0 is -
    Solution

  • Question 5
    1 / -0
    The area of region bounded by  $$x = 0,2 x - 3 y = - 6$$  and  $$2 x + 3 y = 18$$  is
  • Question 6
    1 / -0
    Area of the region bounded by curves y=x log x and $$y={ 2x-x }^{ 2 }$$ is
  • Question 7
    1 / -0
    Area of the region bounded by the curve $$( y - x ) ^ { 2 } = x ^ { 3 }$$ and the line $$x = 1$$ is
    Solution

  • Question 8
    1 / -0
    Area enclosed by the curve $$y = f ( x )$$ defined parametrical as $$x = \frac { 1 - t ^ { 2 } } { 1 + t ^ { 2 } } , y = \frac { 2 t } { 1 + t ^ { 2 } }$$
    Solution

  • Question 9
    1 / -0
    The area (in sq units) of the region bounded by the curve $$y=\sqrt { x } $$ and the lines $$y=0,y=x-2$$, is 
    Solution

  • Question 10
    1 / -0
    The area bounded by the curve y=$${ x }^{ 3 },$$ x-axis and two ordinates x=1 to x=2 equal to 
    Solution

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