Differential Eq...

What is the curve which passes through the point (1, 1) and whose slope is $$\dfrac{2y}{x} $$?

If $$x  dy = y  dx + y^2 dy, y > 0$$ and y(1) = 1, then what is y(-3) equal to?

Solution of the differential equation $$\dfrac { dx }{ x } +\dfrac { dy }{ y } =0$$ is

A solution of the differential equation $${ \left( \dfrac { dy }{ dx }  \right)  }^{ 2 }-x\dfrac { dy }{ dx } +y=0$$ is

The solution of differential equation
$$4xy\cfrac { dy }{ dx } =\cfrac { 3{ \left( 1+x \right)  }^{ 2 }\left( 1+{ y }^{ 2 } \right)  }{ \left( 1+{ x }^{ 2 } \right)  } $$ is 

The solution of the differential equation $$\dfrac { dy }{ dx } +\sin { \left( \dfrac { y+x }{ 2 }  \right)  } +\sin { \left( \dfrac { y-x }{ 2 }  \right)  } =0$$ is

The solution of $$ \dfrac {dy}{dx} + \sqrt{ \left( \dfrac {1-y^2}{1-x^2} \right) } = 0 $$ is :

The solution of the differential equation $$\dfrac { dy }{ dx } ={ e }^{ x-y }\left( { e }^{ x }-{ e }^{ y } \right) $$ is

The solution of the differential equation $$\displaystyle (x^2-yx^2)\frac{dy}{dx}+y^2+xy^2=0$$ is?

The solution of $$\dfrac{dy}{dx} = 1+y+y^2+x+xy+xy^2$$ is