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Electric Charges and Fields Test - 16

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Electric Charges and Fields Test - 16
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  • Question 1
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    When the distance between the charged particles is halved, the force between them becomes

    Solution

    F ∝ 1.r2; so when r is halved the force becomes four times.

     

  • Question 2
    1 / -0

    There are two charges +1μC and + 5μC. The ratio of the forces acting on them will be

    Solution

    The same force will act on both bodies although their directions will be different.

     

  • Question 3
    1 / -0

    In the absence of other conductors, the surface charge density

    Solution

    Surface charge density σ = qA

     

  • Question 4
    1 / -0

    Charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium, if q is equal to

    Solution

    For such type of problem the magnitude of middle charge can be determined if either of the extreme charge is in equilibrium by using the following formula. If charge A is in equilibrium then  q = QB (x1/x)2. If charge B is in equilibrium then q = QA (x2/x)2. If the whole system is in equilibrium then use either of the above formula.

     

  • Question 5
    1 / -0

    The electric field inside a spherical shell of uniform surface charge density is

    Solution

    All charge resides on the outer surface so that according to Gauss law, electric field inside a shell is zero.

     

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