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Electric Charges and Fields Test - 23

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Electric Charges and Fields Test - 23
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  • Question 1
    1 / -0
    Complete the following statements with an appropriate word /term be filled in the blank space(s).

    The force of attraction or repulsion between two charges is given by ......................
    Solution
    Coulomb's law: The force exerted by one point charge is proportional to the product of the charge and varies inversely as the sure of the distance separating the charges.
  • Question 2
    1 / -0
    The ampere-sec stands for the unit of :
    Solution
    Charge is given by the relation, $$q = I*t$$
    so its unit is ampere - sec
  • Question 3
    1 / -0
    A uniform rod of length l and mass m is free to rotate in a vertical plane about A. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is $$\frac{ml^{2}} {3}$$

    Solution
    Here $$\tau$$ = $$I\alpha$$

    $$\Rightarrow \left (mg\right) \left (\frac{l} {2}\right)$$ = $$\left (\frac{ml^{2}} {3}\right) \left (\alpha\right) \Rightarrow \alpha$$ = $$\frac{3g} {2l}$$

  • Question 4
    1 / -0
    Two point charges $$2\ C$$ and $$-6\ C$$ attract each other with a force of $$12\ N$$. A negative charge of $$2\ C$$ is added to each of the above charges, now the force between them is :
    Solution
    When $$-2C$$ is added to $$2C$$ and $$-6C$$, they become $$0C$$ and $$-8C$$ respectively. Since one of the charges is now zero, the force between them is zero.
  • Question 5
    1 / -0
    What happens when some charge is placed on a soap bubble?
    Solution
    The radius of soap bublle increases because of outward force acting on the bubble due to charging
  • Question 6
    1 / -0
    The ratio of electric force between two electrons to two protons separated by the same distance in air is:
    Solution
    $$\cfrac { { F }_{ e } }{ { F }_{ p } } ={ 10 }^{ 0 }=1$$, because force depends only on charges, distance and nature of medium and not type of charge. As all other quantities are same , the ratio will be $$1$$
  • Question 7
    1 / -0
    The laws of forces that govern the force between two electric charges were discovered by :
    Solution
    Coulomb stated that the force (F) of attraction or repulsion between two points charges $$q_1$$ and $$q_2$$ separated by a distance $$r$$ is proportional to the product of the magnitude of the two charges, and inversely proportional to the square of the distance of separation between them. i.e., $$ F \propto \dfrac{q_1 q_2}{r^2}$$
  • Question 8
    1 / -0
    In a region of space having a uniform electric field $$E$$, a hemispherical bowl of radius $$r$$ is placed. The electric flux $$\phi$$ through the bowl is
    Solution
    $$\phi =E(ds)\quad \cos { \theta  } =E(2\pi { r }^{ 2 })\cos { { 0 }^{ o } } =2\pi { r }^{ 2 }E\quad $$
  • Question 9
    1 / -0
    The solid angle subtended by the total surface area of a sphere at the centre is :
    Solution
    steradian is the solid angle subtended at the center of a sphere of radius r by a section of its surface area of magnitude equal to $$ { r }^{ 2 }$$.  Since the surface area is $$ 4\pi { r }^{ 2 }$$, there are $$  4\pi$$ steradians surrounding a point in space.
  • Question 10
    1 / -0
    Electric field lines of force
    Solution
    Electric lines of force are imaginary.
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