Wave Optics Tes...

Two slits in Young's experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, $$\displaystyle \frac{I_{max}}{I_{min}}$$ is 

The ratio of resolving powers of an optical microscope for two wavelengths $$\lambda_1=4000\mathring{A}$$ and $$\lambda_2=6000\mathring{A}$$ is:

In Youngs double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :

Assume that light of wavelength $$600 nm$$ is coming from a star. The limit of resolution of telescope whose objective has a diameter of $$2m$$ is :

If $$f_{0} = 5\ cm, \lambda = 600{A^{0}}, a = 1\ cm$$ for a microscope, then what will be its resolving power.

In a single slit diffraction with $$\displaystyle \lambda =500nm$$ and a lens of diameter 0.1 mm, width of central maxima, obtain on screen at a distance of 1 m will be

 In a $$YDSE$$, the light of wavelength $$\lambda = 5000\overset {\circ}{A}$$ is used, which emerges in phase from two slits a distance $$d = 3\times 10^{-7}m$$ apart. A transparent sheet of thickness $$t = 1.5\times 10^{-7}m$$ refractive index $$\mu = 1.17$$ is placed over one of the slits. What is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of $$y$$.

A : The phase difference between any two points on a wave front is zero
R : From the source light, reaches every point on the wave front in the same time.

A plane wave front falls on a convex lens. The emergent wave front:

Huygens' wave theory is used :