Wave Optics Tes...

A light of wavelength 6300A shine on a two narrow slits separated by a distance 1.0 mm and illuminates a screen at a distance distance 1.5 m away. When one slit is covered by a thin glass of refractive index 1.8 and other slit by a thin glass plate of refractive index $$\Pi $$, the central maxima shifts by $${ 6 }^{ \circ  }$$. Both plates have same thickness of 0.5 mm. The value of refractive index $$\Pi $$ of the plate is 

A beam of light of wavelength $$600\ nm$$ from a distant source falls on a single slit $$1.00\ mm$$ wide and the resulting diffraction pattern is observed on a screen $$2m$$ away. The distance between the first dark fringes on either side of the central bright fringe is

A Young's double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen placed perpendicular to the length of slits is

A point sources $$S$$ emitting light of wavelength $$600\ nm$$ is placed at a very small height $$h$$ above a flat reflecting surface $$AB$$ (see figure). The intensity of the reflected light is $$36\%$$ of the incident intensity. Interference fringes are observed on a screen placed parallel to the reflecting surface at a very large distance $$D$$ from it.What is the shape of the interference fringes on the screen?

Two coherent monochromatic light beams of intensities $$I$$ and $$4I$$ are superposed. The maximum and minimum possible intensities in the resulting beam are:

n identical waves each of intensity $${ 1 }_{ 0 }$$ interfere with each other. The ratio of maximum intensities if the interference is (i) coherent and (ii) incoherent is:

An observer moves towards a stationary source of sound, with a velocity one fifth of the velocity of sound. What is the percentage increase in the apparent frequency?

 Intensity at center in YDSE is $$I_0$$. If one slit is covered, then intensity at center will be:

A small plane mirror is placed at the center of the spherical screen of radius R. A beam of light is falling on the mirror. If the mirror makes n revolutions per second, the speed of light on the screen after reflection from the mirror will be:

If $$\dfrac{I_{1}}{I_{2}}=\dfrac{9}{1}$$ then $$\dfrac{I_{max}}{I_{min}}=?$$