Wave Optics Tes...

If light waves emitted by an ordinary source, for what period of time, the phase remains constant :-

Angle of incidence is equal to the angle of reflection.

Two point source separated by $$d=5\mu m$$ emit light of wavelength $$\lambda=2\mu m$$ in phase. A circular wire of radius $$20\ mu m$$ is placed around the source as shown in figure.

In the interference, two light waves are in the phase difference of at a point. If the yellow light is used, then the color of fringes at that point will be:-

If ratio of amplitude of two interferring source is $$3:5$$. Then ratio of intensity of maxima and minima in interference pattern will be 

In YDSE, d = 2 mm, D = 2 m and$$\lambda $$  = 500 nm. If intensity of two slits are $$l _ { 0 }$$ and $$9 l _ { 0 }$$ then find intensity at  $$y = \frac { 1 } { 6 }$$

What is the path difference of destructive interference :

Statement-1 : In standard YDSE set up with visible light, the position on screen where phase difference is zero appears bright.
and
Statement-2 : In YDSE set up magnitude of electromagnetic field at central bright fringe is not varying with time.

In Y.D.S.E a film of a thickness of $$1.2\mu m$$ having $$2.5\mu m$$ is placed in the path of one slit & glass plate of $$1.5\mu m$$ is placed in front of other slits by which the central bright fringe do not shift, then the thickness of the glass is:-

In a Young's double slit experiment D equals the distance of screen and d is the separation between the slit. The distance of the nearest point to the central maximum where the intensity is same as that due to a single slit, is equal to:-