Dual Nature of ...

During an experiment an $$\alpha $$- particle and a proton are having a difference , their de Broglie wavelenght ratio will be

If the de-Broglie wavelengths associated with a proton and $$  \alpha  $$ -particle are equal, then the ratio of velocities of the proton and the a-particle will be:

If there are two de-Broglie waves formed in an orbit of H-atom then the energy of electron in that orbit is.

An electron with an initial kinetic energy of $$100\ eV$$ is accelerated through a potential difference of $$50\ V$$. Now the de-Broglie wavelength of electron becomes

The anode voltage of a photocell is kept fixed. The wavelength of the light falling on the cathode is gradually changed. The plate current $$I$$ of the photocell varies as follows:

What should be the momentum (in gram centimetre per second) of a particle if its de-Broglie wavelength is 1 angstrom and the value of his $$6.6252 \times 10 ^ { - 27 }$$ erg second ? 

The ratio of de-Broglie wavelengths of molecules of hydrogen and helium which are at temperature $$27^oC$$ and $$127^oC$$ respectively is

Monochromatic radiation emitted when electron on hydrogen atom jumps from first exited to the grounds state irradiates a photosnesitive material. The stopping potential is measured to be 3.57V. The threshold frequency of the material is :

If a photon having wavelength $$6.2 { nm }$$ was allowed to strike a metal plate having work function $$50 { eV }$$, then calculate wavelength associated with emitted electron.

de-Broglie equation is