Nuclei Test - 2...

The overall process of carbon nitrogen fusion cycle results in the fusion of 4 protons to yield helium nucleus and :

In Carbon-Nitrogen fusion cycle , protons are fused to form a helium nucleus, positrons and release some energy.The number of protons fused and the number of positrons released in this process respectively are

Energy in the sun is due to 

$$1$$ kg of iron (specific heat $$120$$ Cal kg$$^{-1}$$C$$^{-1}$$) is heated by $$1000$$$$^{0}$$C. The increase in its mass is :

The mass defect for the nucleus of Helium is $$0.0303 \ amu$$. The binding energy per nucleon in $$MeV$$ is

The mass defect and binding energy per nucleon of an alpha particle are :
(Mp $$=$$ 1.00734$$u$$, Mn $$=$$ 1.00874$$u$$, M $$=$$ 4.0015$$u$$)

The binding energy of an imaginary iron $$^{56}_{36}Fe$$ is $$\underline{\hspace{0.5in}}$$
(Given atomic mass of Fe is 55.9349 amu and that of hydrogen is 1.00783 amu. Mass of neutron is 1.00876 amu)

The masses of $$\alpha $$ -particle, proton and neutron are $$4.00150$$ amu, $$1.00728$$ amu and $$1.00867$$ amu respectively. Binding Energy per nucleon of $$\alpha$$ -particle is :

The mass defect in $$_{2}He^{3}$$ is $$\underline{\hspace{0.5in}}$$ , if m$$_{p} =$$1.00727 amu, $$m_{n} =$$1.008665 amu, mass of $$_{2}He^{3} =$$3.01664 amu

The binding energy of an $$\alpha $$ -particle is
(Given that mass of proton$$=$$$$1.0073$$ amu, mass of neutron$$=$$ $$1.0087$$ amu, and mass of $$\alpha $$-particle$$=$$$$4.0015$$ amu)