Semiconductor Electronics: Materials, Devices and Simple Circuits Test 8

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Semiconductor Electronics: Materials, Devices and Simple Circuits Test 8

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Weekly Quiz Competition

Question 1
1 / -0

The symbol represents

A
NOT gate

B
OR gate

C
AND gate

D
NOR gate

Solution

The symbol represented above by definition is of NAND gate which gives output only when both the input signals are low i.e $$0$$
Question 2
1 / -0

In the Boolean algebra, of the following one which is not equal to $$A$$ is

A
$$A.A$$

B
$$A + A$$

C
$$\bar{A}.A$$

D
$$\overline{\bar A + \bar A}$$

Solution

The truth table for AND gate is given as shown in the figure.
When $$A$$ is true, $$\bar{A}$$ is false and vice versa.
Hence value of $$\bar{A}.A$$ is always false(looking at the second and third row of the table) which is not equal to $$A$$.
Hence, option C is the answer.
Question 3
1 / -0

In the Boolean algebra : $$A + B =$$

A
$$\bar{A}$$+$$\bar{B}$$

B
A.B

C
$$\bar{\bar{A}}+\bar{\bar{B}}$$

D
$$\bar{\bar{A}}$$+$$\bar{B}$$

Solution

Input $$\bar A+\bar B$$ $$A.B$$ $$\bar{\bar A} + \bar{\bar B}$$ $$\bar {\bar A} + \bar B$$
$$A=B=0$$ 1 0 0 1
$$A=B=1$$ 0 1 1 1
$$A=0, B=1$$ 1 0 1 1
$$A=1, B=0$$ 1 0 1 1
Question 4
1 / -0

The gate that has only one input terminal

A
NOT

B
NOR

C
NAN

D
XOR

Solution

Only one logic gate has one input terminal i.e. NOT gate.
Question 5
1 / -0

If $$A = 1$$ and $$B = 0$$, then in terms of Boolean algebra the value of $$A.A + B$$ is

A
$$A$$

B
$$B^2$$

C
$$B$$

D
$$A \cdot B$$

Solution

For $$A=1$$ and $$B=0$$
$$A.A+B=1.1+0=1$$

Hence, $$A.A+B=A$$ ............(since, $$A=1$$)
Question 6
1 / -0

If $$A = 1, B = 0$$ then the value of $$\bar {A} + B $$ in terms of Boolean algebra is

A
$$A$$

B
$$B$$

C
$$B + A$$

D
$$A.\bar{B}$$

Solution

For $$A = 1, B = 0$$
$$\bar A+B = \bar 1 + 0 = 0 + 0 = 0$$
Hence, $$\bar A+B = B$$ .............(since, $$B= 0$$)
Question 7
1 / -0

The following one represents logic addition is

A
$$1 + 1 = 2$$

B
$$1 + 1 = 10$$

C
$$1 + 1 = 1$$

D
$$1 + 1 = 11$$

Solution

Logic addition is the addition of binary numbers, it is represented by
$$1 + 1 = 1$$
Question 8
1 / -0

NOR gate is the series combination of

A
NOT gate followed by OR gate.

B
OR gate followed by NOT gate.

C
AND gate followed by OR gate.

D
OR gate followed by AND gate.

Solution

Truth table of NOR is complement of OR. That's why NOR is combination of OR gate followed by NOT gate.

Question 9

1 / -0

In the Boolean algebra : $$\bar{A} . \bar{B}=$$ ......

$$\overline{A+B}$$

$$A.B$$

$$\overline{\bar A + \bar B}$$

$$A + B$$

Solution

Input	$$\bar {A}.\bar {B} $$	$$\overline {A+B}$$	A.B	$$\overline {\bar A+\bar B}$$	A+B
$$A=B=0$$	1	1	0	0	0
$$A=B=1$$	0	0	1	1	1
$$A=0, B=1$$	0	0	0	1	1
$$A=1, B=0$$	0	0	0	1	1

Question 10
1 / -0

Identify the logic gate in figure.

A
NAND

B
NOR

C
NOT

D
AND

Solution

The symbol of circle shown in figure with OR gate indicates the NOT gate hence, given gate is NOR gate.

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Re-Attempt Weekly Quiz Competition

Input	$$\bar A+\bar B$$	$$A.B$$	$$\bar{\bar A} + \bar{\bar B}$$	$$\bar {\bar A} + \bar B$$
$$A=B=0$$	1	0	0	1
$$A=B=1$$	0	1	1	1
$$A=0, B=1$$	1	0	1	1
$$A=1, B=0$$	1	0	1	1

Semiconductor Electronics: Materials, Devices and Simple Circuits Test 8

Result

Semiconductor Electronics: Materials, Devices and Simple Circuits Test 8

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SHARING IS CARING

Question 1

NOT gate

OR gate

AND gate

NOR gate

Solution

Question 2

$$A.A$$

$$A + A$$

$$\bar{A}.A$$

$$\overline{\bar A + \bar A}$$

Solution

Question 3

$$\bar{A}$$+$$\bar{B}$$

A.B

$$\bar{\bar{A}}+\bar{\bar{B}}$$

$$\bar{\bar{A}}$$+$$\bar{B}$$

Solution

Question 4

NOT

NOR

NAN

XOR

Solution

Question 5

$$A$$

$$B^2$$

$$B$$

$$A \cdot B$$

Solution

Question 6

$$A$$

$$B$$

$$B + A$$

$$A.\bar{B}$$

Solution

Question 7

$$1 + 1 = 2$$

$$1 + 1 = 10$$

$$1 + 1 = 1$$

$$1 + 1 = 11$$

Solution

Question 8

NOT gate followed by OR gate.

OR gate followed by NOT gate.

AND gate followed by OR gate.

OR gate followed by AND gate.

Solution

Question 9

$$\overline{A+B}$$

$$A.B$$

$$\overline{\bar A + \bar B}$$

$$A + B$$

Solution

Question 10

NAND

NOR

NOT

AND

Solution

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