Electrostatic P...

The potential difference across $$3 \mu F$$ condenser is :

Two condensers of capacitance $$4\mu F$$ and $$5\mu F$$ are joined in series. If the potential difference across $$5\mu F$$ is $$10V$$, then the potential difference across $$4\mu F$$ condenser is :

Charge Q taken from the battery of 12V in the circuit is :

The equivalent capacitance of the network given below is$$1 \mu F$$. The value of C is:

Three capacitors $$2\mu F, 3\mu F$$ and $$5\mu F$$ are connected in parallel. The capacitance of the combination:

The ratio of the resultant capacities when three capacitors of $$2 \mu F , 4 \mu F$$ and $$6 \mu F$$ are connected first in series and then in parallel is

The maximum and minimum resultant capacity that can be obtained with $$2\mu F, 3\mu F$$ and $$6\mu F$$ are respectively:

Three capacitors $$2\mu F, 3\mu F$$ and $$6\mu F$$ are connected in series. The effective capacitance of the combination is:

A parallel plate condenser has initially air medium between the plates. If a slab of dielectric constant 5 having thickness half the difference of separation between the plates is introduced, the percentage increase in its capacity is :

Two identical metal plates separated by a distance $$d$$ forms parallel plate capacitor of capacity $$C$$. A metal sheet of thickness $$d/2$$ and same dimensions is inserted between the plates, so that the air gap is separated into two equal parts. The new capacity of the system will be: