Electrostatic P...

The electric potential decreases uniformly from 120 V to 80 V as one moves on the X-axis from $$ x = -1 cm$$ to $$x = +1$$ cm. The electric field at the origin.

The equivalent capacitance between A and B in the circuit given below, is:

Let  $$V_0$$ be the potential at the origin in an electric field $$\overset{\rightarrow}{E}=E_x\hat{i}+E_y\hat{j}$$. The potential at the point $$(x,y)$$ is:

The electric potential at a distance of $$3 \,m$$ on the axis of a short dipole of dipole moment $$4\times 10^{-12}$$ coulomb-metre is 

Two charges $$-5\mu C$$ and $$+10\mu C$$ are placed 20 cm apart. The net electric field at the mid-point between the two charge is 

In the following question the value of equivalent capacitane between point a & b is:-

In the circuit diagram given below, the value of the potential difference across the plates of the capacitors are 

A parallel plate capacitor of area $$60 cm^2$$ and separation 3 mm is charged initially to $$90 \mu C$$. If medium between the plates gets slightly conducting and the p!ate loses the charge initially at rate of $$2.5\times10^{-8}  C/s$$, then what is the magnetic field between the plates?    

Then output in the circuit of figure is taken across a capacitor. It is as shown in figure:-

Calculate the equivalent capacity of the system of capacitors shown across A and B