Electrostatic P...

Find equivalent capacitance between points  $$A$$  and  $$B$$ 

The capacity of parallel plate condenser is $$ 12 \mu F $$. What is its new capacity if the separation between the plates is doubled and the area is halved?

Five conducting parallel plates having area A and separation between them d, are placed as shwon in the figure. plate number 2 and 4 are connected wire and between point A and B , a cell of emf E is connected. the charge flown through the cell is 

Find equivalent capacitance between A and b of the given circuit.

In the circuit in the figure,in steady state,

Two capacitor of capacity $$C_{1}$$ and $$C_{2}$$ are connected in series. The combined capacity $$C$$ is given by

When two capacitors are connected in parallel the resulting combination has capacitance $$10uF$$.  The same capacitors when connected in series results in a capacitance $$0.5uF$$. The respective values of individual capacitors are

Energy stored per unit volume of a parallel plate capacitor having plate area A and plate separation d charged to a potential V volt is

A neutral spherical copper particle has a radius of $$10\ nm (1nm = 10^{-9}m)$$. It gets charged by applying the voltage slowly adding one electron at a time. Then the graph of the total charge on the particle vs the applied voltage would look like:

Five identical capacitors, of capacitance $$20\mu F$$ each, are connected to a battery of $$150V$$, in a combination as shown
in the diagram. What is the total amount of charge stored?