Electrostatic P...

In the given network of capacitors as shown in figure, given that $${ C }_{ 1 }=C_{ 2 }={ C }_{ 3 }=400pF$$ and $$C_{ 4 }={ C }_{ 5 }={ C }_{ 6 }=200pF$$. The effective capacitance of the circuit between $$X$$ and $$Y$$ is :

An uncharged parallel plate capacitor having a dielectric of dielectric constant $$K$$ is connected to a similar air cored parallel plate capacitor charged to a potential $${V}_{0}$$. The two share the charge, and the common potential becomes $$V$$. The dielectric constant $$K$$ is :

Two parallel plate capacitors of capacitances $$C$$ and $$2C$$ are connected in parallel and charged to a potential difference $$V$$. The battery is then disconnected, and the region between the plates of $$C$$ is filled completely with a material of dielectric constant $$K$$. The common potential difference across the combination becomes :

The equivalent capacitance of the circuit across the terminals $$A$$ and $$B$$ is equal to :

The plates of a parallel plate capacitor are charged upto $$100V$$. now, after removing the battery, a $$2mm$$ thick plate is inserted between the plates. Then, to maintain the same potential difference, the distance between the capacitor plates is increased by $$1.6mm$$. The dielectric constant of the plate is :

In the figure, identical capacitors are connected in the given three configurations. The ratio of the total capacitances in (i), (ii) and (iii) respectively, is :

Consider the figure given. Each capacitor has capacitance $$C$$. The equivalent capacitance between $$1$$ and $$3$$ is :

An electric charge $$10^{-3}\mu C$$ is placed at the origin (0, 0) of X-Y co-ordinate system. Two points A and B are situated at $$(\sqrt 2, \sqrt 2)$$ and (2, 0) respectively. The potential difference between the points A and B will be :

Consider the figure given. Each capacitor has capacitance $$C$$. The capacitance between $$1$$ and $$3$$ is :

An air capacitor of capacity $$C=10\mu F$$ is connected to a constant voltage battery of $$12$$ volt. Now the space between the plates is filled with a liquid of dielectric constant $$5$$. The (additional) charge that flows now from battery to the capacitor is :