Electrostatic P...

The effective Capacitance in μFμF in between A and B will be.

the plates of a parallel plate capacitor are separated by a distance d with air as the medium between the plates.in order to increase the capacitance by 66% a dielectric slab of dielectric constant 5 is introduced between the plates what is the thickness of the sielectric slab?

An electric field of $$200V{m^{ - 1}}$$ exists in the region between the plates of a parallel plate capacitor of plate separation $$5cm$$. The potential difference between the plates when a slab of dielectric constant $$4$$ and thickness $$1cm$$ is inserted between the plates is:

Two capacitor $$ C_1 and C_2 $$ are connected in a circuit as shown in figure. the potential difference $$ (V_A-V_B) $$ is:

The equivalent capacitance between P & Q in the figure is.

In the given circuit $$C_{effective}  = 0.5$$. Find the value of C. 

Electric potential $$(\phi )$$ of a quadrupole varies with distance 'r' on its axis as :-

What is the  equivalent capacitance between A and B in the circuit at steady state shown.

The correct graph between the gravitational potential $$(v_{g})$$ due to a hollow sphere and distance from centre will be

Find equivalent capacitance across AB (all capacitances in $$\mu F$$)