Electrostatic P...

Find equivalent capacitance between $$A$$ and $$B$$. 

The equivalent capacitnce $$C_{AB}$$ of the circuit is shown in the figure is

In the arrangement shown in the figure each capacitor has a capacitance $$1\mu F$$. Find the equivalent capacitance across AB. 

The diagram shows two capacitors with capacitance and breakdown voltages as mentioned. What should be the maximum value of the external emf source such that no capacitor undergoes breaks down ?

Four plates are located of a distance 'd' apart from one another. The extreme plates are inter connected. A  potential difference of V is applied to inner plates. The electric field E between '1' and '2' plates is :-

In the following circuit, The resultant capacitance between A and B is $$1\mu F$$ Then value of C is 

Consider the situation as shown in figure. The variation of potential as one moves from left to right along branch containing the capacitors, is :-

Six indentical capacitors are joined in parallel charged to a potential difference of $$10\, Volt$$, separated and then connected in serise, i.e. The positive plate of one is connected to the negative plate of the other. Then the potential difference between the free plates is -

Two conductors,  each of capacitance 1F are charged to potential of 10 V and 6 V respectively.  They are  then joined together.  Their common potential will be 

Two capacitors of capacitances $$4\mu F$$ and $$6\mu F$$ are connected across a 120 V battery in series with each other. What is the potential difference across the $$4\mu F$$ capacitor?