Electrostatic Potential and Capacitance Test

Result

Electrostatic Potential and Capacitance Test - 9

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Question 1
1 / -0

The amount of charge a capacitor can store when a potential diffrence of 1V is applied across it is called its

A
resistance

B
capacitance

C
reactance

D
inductance

Solution

Q = CV
When V = 1
Thus, Q = C
Question 2
1 / -0

A variable capacitor and an electroscope are connected in parallel to a battery. The reading of the electroscope would be decreased by

A
Decreasing the battery potential

B
Placing a dielectric between the plates

C
Decreasing the distance between the plates

D
Increasing the area of overlapping of the plates

Solution

An electroscope is a device which measures the potential difference. If it is connected in parallel to the capacitor, the potential across it will be equal to the potential across the capacitor, which is equal to the potential across the battery. On decreasing the battery potential, the potential difference across the electroscope reduces and hence the reading reduces.
Question 3
1 / -0

An electrolytic capacitor is marked 8 μF, 220 V. It can be used in a circuit where the p.d. across the capacitor may be

A
300 V

B
1000 V

C
200 V

D
500 V

Solution

The break down potential of the capacitor is 220 V. In order to prevent damage to a capacitor, it should be always used in a circuit where the p.d is less than its break down potential. The p.d difference can be 200 V.
Question 4
1 / -0

The action of the dielectric to increase the capacitance is due to

A
dipole orienting parallel to the plates

B
electric polarization

C
movement of charges to the sides of dielectric

D
neutralization of charges

Solution

When a dielectric is placed between the plates of a capacitor, electric polarization results in a reverse electric field inside the dielectric. The net electric field reduces and therefore the potential reduces.
Since, C = Q/V
Thus, the capacitance increases.