Current Electri...

Three resistors of $$4.0\ \Omega$$, $$6.0\ \Omega$$ and $$10.0\ \Omega$$ are connected in series. What is their equivalent resistance?

Two students set up their circuits for finding the equivalent resistance of two resisto connected in series in two different ways as shown.
The circuit (s) likely to be labelled as incorrect :

Two wires of same metal have the same length but their cross-sections area in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is $$10\Omega$$ .The total resistance of the combination will be:

The resistors of resistances $$2 \Omega, 4 \Omega, 5 \Omega$$ are connected in parallel. The total resistance of the combination will be :

What is the maximum resistance one can make with ten $$1 \Omega$$ resistors?

The value of current $$i$$ in the given circuit is:

A battery of 20 cells (each having e.m.f. 1.8 volt and internal resistance 0.1 ohm) is charged by 220 volts and the charging current is 15A. The resistance to be put in the circuit is

If a resistance $$5\Omega $$ is connected in the left gap of a meter bridge and $$15\Omega $$ in the other gap then position of balancing point is

Five resistors each of 1 ohm are connected in parallel. The resultant resistance of the combination is :

Kirchhoff's second law is based on the law of conservation of