Moving Charges and Magnetism Test

Result

Moving Charges and Magnetism Test - 3

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Question 1
1 / -0

The magnetic field in the interior of the solenoid was shown to be given by B₀ = μ₀nI, if the interior of the material is filled with non-zero magnetization, the field inside the solenoid will be,

A
greater than B₀

B
equal to B₀

C
lesser than B₀

D
zero

Solution

When the interior of the solenoid is filled with a material with non-zero magnetization, the field inside the solenoid will be greater than B₀. The net B field in the interior of the solenoid may be expressed as

B = B₀ + B_m, where B_m is the field contributed by the material core.
Question 2
1 / -0

A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 2A. If the number of turns is 1000 per meter. The value of magnetizing current (I_M) is equal to,

A
864 A

B
794 A

C
764 A

D
zero

Solution

The magnetizing current I M is the additional current that needs to be passed through the windings of the solenoid in the absence of the core which would give a B value as in the presence of the core.

Thus,

B = µ_r n₀ (I + I_M).

Using the parameters given in the question, I = 2A, B = 1 T

We get

The magnetic field B is given by B = µ_r µ₀ H = 400 × 4π × 10^-7× 2 × 10³ = 1.0 T

Therefore,

B = µ_r n₀ (I + I_M).

1 = 400 × 4π × 10^-7(2 + I_M)

I_M = 794 A.