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Magnetism and Matter Test 26

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Magnetism and Matter Test 26
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The potential energy of a bar magnet of magnetic moment $$M$$ placed in a magnetic field of magnitude $$B$$ such that it makes an angle $$\theta$$ with the direction of $$B$$ is:
    Solution
    undefined

  • Question 2
    1 / -0
    The primary origin of magnetism lies in the
    Solution
    Atomic currents and intrinsic spins of electrons are responsible for origin of magnetism.
  • Question 3
    1 / -0
    If $$B_E$$ represents equatorial magnetic field and $$B_A$$ represents axial magnetic field due to a bar magnet. Which of the following relationships between $$B_E$$ and $$B_A$$ is correct?
    Solution
    As equatorial magnetic field due to bar magnet is 
    $$B_E = \dfrac{\mu_0 m}{4 \pi^3}$$    .....(i)
    and axial magnetic field due to bar magnet is
    $$B_A = \dfrac{\mu_0}{4 \pi} \dfrac{2m}{r^3} $$  .... (ii)

    From (i) and (ii), we get
    $$B_A$$ = $$2B_E$$
  • Question 4
    1 / -0
    If you made a map of magnetic field lines at Melbourne in Australia, then the magnetic field lines seem to be
    Solution
    As Melbourne is situated in southern hemisphere where north pole of earth's magnetic field lies therefore magnetic lines of force seem to come out of the ground.
  • Question 5
    1 / -0
    Mark the correct set of ferromagnetic substances,
    Solution
    Iron, cobalt and nickel are the examples of ferromagnetic material.
  • Question 6
    1 / -0
    Which of the following property shows the property of ferromagnetic substances?
    Solution
    Ferromagnetic material depends on temperature as for $$T<T_{c}(Curie's Temperature)$$ it acts as a ferromagnet.
    $$T>T_{c}$$ acts as a paramagnet.

  • Question 7
    1 / -0
    The equatorial magnetic field of earth is $$0.4$$G. Then its dipole moment on equator is
    Solution
    Assuming the Earth's magnetic field is due to a bar magnet at center of the Earth, held along the polar axis of Earth, the equatorial magnetic field of Earth is given by
    $$B=\dfrac{\mu_0 M}{4\pi r^3}$$

    where,
    $$r=$$ Radius of earth $$=6400\ km=6.4\times 10^6\ m$$
    $$M=$$ Earth's magnetic dipole  moment

    Given $$B= 0.4\ G= 0.4\times 10^{-4}\ T$$

    $$\therefore M=\dfrac{Br^3}{\dfrac{\mu_o}{4\pi}}= \dfrac{(0.4\times 10^{-4})(6.4\times 10^6)^3}{10^{-7}}$$

    $$\therefore M=1.05 \times 10^{23} Am^2$$

    So, option $$A$$ is correct
  • Question 8
    1 / -0
    The strength of the earth's magnetic field is
    Solution
    The strength of the earth magnetic field is not constant. It varies from one place to other place on the surface of earth. Its value being of the order of $$10^{-5}$$T.
  • Question 9
    1 / -0
    The earth's field departs from its dipole shape substantially at large distance (greater than about $$3000$$ km). The responsible factor for this distortion is then
    Solution
    Due to motion of ions in earth's ionosphere the earth's magnetic field gets modified.
  • Question 10
    1 / -0
    Which of the following is universal magnetic property.?
    Solution
    Diamagnetism is universal. It is present in all materials. But it is weak and hard to detect if the substance is para or ferromagnetic
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