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Electromagnetic Waves Test - 14

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Electromagnetic Waves Test - 14
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  • Question 1
    1 / -0
    The propagation constant of a photon of wavelength $$6284 \ A^o$$ 
    Solution
    The propagation constant can be written as 
    $$K= \dfrac{2 \pi}{ \lambda}=\dfrac{60284}{6284 \times 10^{-8}}= 10^{5} cm^{-1}$$
  • Question 2
    1 / -0

    The frequency of incident light falling on a photosensitive metal plate is doubled, the kinetic energy of the emitted photoelectrons is

    Solution
    $$v \rightarrow 2v$$             $$hv-hv_o = K G_{max}$$
    So, $$KG_{max}  >  2  KG_{max}$$
    as $$hv_o $$ is constant
  • Question 3
    1 / -0
    Choose the correct answer from the alternatives given.
    Displacement current goes through the gap between the plates of a capacitor when the charge of the capacitor
    Solution
    Displacement current inside a capacitor is given by:-

    $$i_d=\epsilon_0  \dfrac{\phi_E}{dt}$$

    where $$\phi_E$$ is the electric flux inside the capacitor

    The displacement current is developed inside a capacitor when there is a change in the electric flux linked with the capacitor. The change in electric flux can occur in both the cases either the charge increases or decreases on the capacitor. This will lead to a change in flux linked with the coil.

    Thus, option $$(C)$$ is correct.
  • Question 4
    1 / -0
    In case of the electromagnetic waves the angle between the electric and magnetic field vectors is
    Solution
    Electromagnetic waves are formed when an electric field  couples with a magnetic field . The magnetic and electric fields of an electromagnetic wave are perpendicular to each other and to the direction of the wave, as shown in figure

  • Question 5
    1 / -0
    Instantaneous displacement current $$1A$$ in the space between the parallel plates of $$1\mu F$$ capacitor can be established by changing the potential difference at the rate of:
    Solution
    In a capacitor of capacitance $$C$$,
    $$V=\dfrac{q}{C}$$
    $$\implies \dfrac{dV}{dt}=\dfrac{i}{C}=\dfrac{1A}{1\mu F}=10^{6}V/s$$
  • Question 6
    1 / -0
    The displacement current was first populated by
    Solution
    In electromagnetism, displacement current is a quantity appearing in Maxwell's equations that is defined in terms of the rate of change of electric displacement field.
  • Question 7
    1 / -0
    Displacement current is
    Solution

  • Question 8
    1 / -0
    According to Maxwell's hypothesis, a changing electric field gives rise to
    Solution
    $$Answer:-$$ C option
    $$\nabla \times B={ \mu  }_{ 0 }(J+{ \epsilon  }_{ 0 }\dfrac { dE }{ dt } )$$
    using this equation of maxwell we can say changing electric field $$\dfrac{dE}{dt}$$ induces magnetic field.
  • Question 9
    1 / -0
    Maxwell's equation describe the fundamental laws of
    Solution
    Maxwell's equation describe the fundamental laws of electricity and magnetism. His equations describe how electric and magnetic fields are generated and altered by each other and by charges and currents.
  • Question 10
    1 / -0
    According to Maxwell's equation, the velocity of light in any medium is expressed as
    Solution
    Velocity of light in a medium,

    $$\displaystyle c=\frac{1}{\sqrt{\mu_0\varepsilon_o\mu_r\varepsilon_r}}=\frac{1}{\sqrt{\mu\varepsilon}}$$
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