Ray Optics and Optical Test

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Ray Optics and Optical Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

The apparent depth of an object lying in a denser medium is always ......... than the real depth

A
Greater

B
Lesser

C
Equal

D
None

Solution

The apparent depth of an object lying in a dense need always less than its real depth for all angles of observation in a rarer medium.
Question 2
1 / -0

A manufacturer uses a concave lens instead of a convex lens in a magnifying glass by mistake. What will be the effect on the working of the lens?

A
Images will be blurred.

B
Images will be clearer.

C
Images will be diminished.

D
Images will be further magnified.

Solution

Images formed by a concave lens are always diminished.
Question 3
1 / -0

A magnifying glass is used to read the newspaper. As it is moved far away from the newspaper

A
Text becomes blurred and magnification reduces

B
Text becomes more focussed and magnification reduces

C
Text becomes more focused and magnification increases

D
Text becomes blurred and magnification increases

Solution

As the magnifying lens(convex lens) is moved far away from the eye, the image formed is real and inverted and is formed inside the human eye and hence it blurs. Since the object is far away from the mirror, the image formed is diminished and hence magnification reduces.
Question 4
1 / -0

Shift by which the object appears to be raised depends on

A
The refractive index of the medium

B
The thickness of denser medium

C
Colour of incident light

D
All

Solution

Shift by which the object appears to be raised depends on these 4 factors. The shift increases with increase in refraction index of medium and also with the thickness of denser medium.
Question 5
1 / -0

Choose the correct option

A
A: Virtual Image

B: Real Image

B
A: Real Image

B: Virtual Image

C
A: Real Image

B: Real Image

D
A: Virtual Image

B: Virtual Image

Solution

As shown in figure A, a virtual image is formed because refracted rays only appear to meet at the image.
As shown in figure B, a real image is formed because refracted rays actually meet at the image.
Question 6
1 / -0

Figure shows the ray diagram of a

A
Simple microscope

B
Compound microscope

C
Simple Telescope

D
Compound Telescope

Solution

The given figure is representing the ray diagram of a simple microscope.
Question 7
1 / -0

$$\mu_V > \mu_R$$ indicates

A
Shift is more for violet colour

B
Shift is more for red colour

C
Shift is equal for both red and voilet

D
All

Solution

Since, $$\mu_V > \mu_R$$, the shift is more for he violet light than the red light in a given medium.
Question 8
1 / -0

The shift by which object appears to be raised ....... with the increase in the thickness of the denser medium.

A
Increases

B
Decreases

C
Both

D
None

Solution

The shift increase with the increase in the thickness of the denser medium, but the shift decrease with the increase in wavelength of light used.
Question 9
1 / -0

What is the formula for spherical mirrors for object distance p and image distance q ?

A
$$\dfrac{1}{p}+q=\dfrac{1}{f}$$

B
$$\dfrac{1}{p}+\dfrac{1}{q}=\dfrac{1}{f}$$

C
$$\dfrac{1}{p}+\dfrac{1}{q}=f$$

D
$$p+\dfrac{1}{q}=\dfrac{1}{f}$$

Solution

Mirror formula is given as:
$$ \dfrac{2}{R} = \dfrac{1}{v} + \dfrac{1}{u} $$

where, $$ R $$ is the radius of curvature of the spherical mirror
$$u $$ is the object distance from the pole
$$ v $$ is the image distance from the pole

We know,
$$ f = \dfrac{R}{2} $$

$$ \Rightarrow \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u} $$

$$ \therefore $$ For object distance $$ p $$ and image distance $$ q $$, mirror formula becomes
$$ \dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q} $$

Hence, the correct answer is OPTION B.
Question 10
1 / -0

When is the real image formed?

A
when the rays of light after reflection or refraction actually go away from some point

B
when the rays of light after reflection or refraction actually meet at some point

C
when the sun rays after reflection or refraction actually meet at some point

D
when the rays of light after deflection actually meet at some point

Solution

Correct answer is (b).

Real image formed when the rays of light after reflection or refraction actually converge at some point and when objects are placed outside the focal length of a converging lens or outside the focal length of a converging mirror.

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Re-Attempt Weekly Quiz Competition

Ray Optics and Optical Test - 19

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Ray Optics and Optical Test - 19

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Question 1

Greater

Lesser

Equal

None

Solution

Question 2

Images will be blurred.

Images will be clearer.

Images will be diminished.

Images will be further magnified.

Solution

Question 3

Text becomes blurred and magnification reduces

Text becomes more focussed and magnification reduces

Text becomes more focused and magnification increases

Text becomes blurred and magnification increases

Solution

Question 4

The refractive index of the medium

The thickness of denser medium

Colour of incident light

All

Solution

Question 5

A: Virtual ImageB: Real Image

A: Real ImageB: Virtual Image

A: Real ImageB: Real Image

A: Virtual ImageB: Virtual Image

Solution

Question 6

Simple microscope

Compound microscope

Simple Telescope

Compound Telescope

Solution

Question 7

Shift is more for violet colour

Shift is more for red colour

Shift is equal for both red and voilet

All

Solution

Question 8

Increases

Decreases

Both

None

Solution

Question 9

$$\dfrac{1}{p}+q=\dfrac{1}{f}$$

$$\dfrac{1}{p}+\dfrac{1}{q}=\dfrac{1}{f}$$

$$\dfrac{1}{p}+\dfrac{1}{q}=f$$

$$p+\dfrac{1}{q}=\dfrac{1}{f}$$

Solution

Question 10

when the rays of light after reflection or refraction actually go away from some point

when the rays of light after reflection or refraction actually meet at some point

when the sun rays after reflection or refraction actually meet at some point

when the rays of light after deflection actually meet at some point

Solution

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A: Virtual Image

B: Real Image

A: Real Image

B: Virtual Image

A: Real Image

B: Real Image

A: Virtual Image

B: Virtual Image