Ray Optics and Optical Test

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Ray Optics and Optical Test - 38

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Weekly Quiz Competition

Question 1
1 / -0

The incident ray, the normal at the point of incidence and the refracted ray:

A
lie on mutually orthogonal planes

B
lie on mutually parallel planes

C
lie on the same plane

D
lie on different arbitrary planes

Solution

The incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane. This is according to the law of refraction.
Question 2
1 / -0

Principal axis is the line joining the pole and the:

A
Principal line

B
Centre of curvature

C
Mirror

D
None of these

Solution

A straight line passing through the pole and the center of curvature of a spherical mirror is called the principal axis.
Question 3
1 / -0

Due to refraction, when seen from outside, a coin placed under water in a bowl, appears to

A
go down

B
come up

C
stay where it is

D
move toward left

Solution

When seen from outside, a coin placed under water in a bowl appears to come up. This happens due to refraction of light.
Question 4
1 / -0

The primary phenomenon in the working of lens is

A
Reflection

B
Refraction

C
Scattering

D
Diffusion

Solution

In a lens, image formation happens using laws of refraction.
Question 5
1 / -0

Occurrence of mirage in deserts in summer is an example of ..........................

A
reflection of light

B
refraction of light

C
propagation of sound

D
conduction of heat

Solution

A mirage is a naturally occurring optical phenomenon in which light rays bend when passing through the layers of the atmosphere with variable density.
Question 6
1 / -0

Telescope forms

A
Real Image

B
Virtual Image

C
Both A and B

D
Neither A nor B

Solution

The objective lens of telescope forms a real image while eyepiece forms a virtual image. The first lens, called the objective, forms a real image within the focal length of the second lens, which is called the eyepiece. The image of the objective lens serves as the object for the eyepiece, which forms a magnified virtual image that is observed by the eye.
Question 7
1 / -0

A glass slab is placed in a medium of higher refractive index than glass. A light ray incident from one surface exits from opposite surface. Then,

A
Angle of emergence = angle of incidence

B
Emergent ray is parallel to incident ray

C
Behaviour is similar to glass slab in air

D
All of the above

Solution

The effect of placing glass slab in a medium of higher index is that the emergent light ray will laterally shift in the opposite direction than that in air.
For first surface,
$$\mu = sin(i)/sin(r)$$............(1)
For second surface,
$$1/\mu = sin(r)/sin(e)$$.........(2)
From (1) and (2),
$$sin(i)=sin(e)$$
Hence, emergent ray is laterally shifted w.r.t incident ray. Thus, behavior is similar to glass slab in air.
Question 8
1 / -0

According to laws of refraction, refraction of light at the boundary between two different regions follow:

A
that the incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane.

B
that for a given pair of media and given colour of light, the ratio of the sine of angle of incidence to the sine of angle of refraction is constant.

C
both A and B

D
neither A nor B

Solution

Refraction of light obeys the following two laws:
1. The incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane.
2. For a given pair of media and given the colour of light, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant.

The second postulate is also known as Snell's Law which is as:
$$\dfrac{sini}{sinr}=\dfrac{n_2}{n_1}$$= $$constant$$
Question 9
1 / -0

Light enters from denser to rarer medium. Choose the correct option.

A
Angle of refraction = Angle of incidence

B
Angle of refraction > Angle of incidence

C
Angle of refraction < Angle of incidence

D
Angle of refraction $$\geq$$ Angle of incidence

Solution

As seen in figure when light travels from denser to rarer medium, light bends away from normal and hence angle of refraction>angle of incidence
Question 10
1 / -0

A man sees a small stationary fish deep in a very clear lake and shoots it accurately. He will

A
hit the fish

B
miss the fish

C
hit but fish will not die

D
may hit or miss depending on the bullet

Solution

Due to refraction, fish will appear displaced from its actual position. The man sees the apparent position of the fish. Hence, the bullet will miss the fish.

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Re-Attempt Weekly Quiz Competition

Ray Optics and Optical Test - 38

Result

Ray Optics and Optical Test - 38

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SHARING IS CARING

Question 1

lie on mutually orthogonal planes

lie on mutually parallel planes

lie on the same plane

lie on different arbitrary planes

Solution

Question 2

Principal line

Centre of curvature

Mirror

None of these

Solution

Question 3

go down

come up

stay where it is

move toward left

Solution

Question 4

Reflection

Refraction

Scattering

Diffusion

Solution

Question 5

reflection of light

refraction of light

propagation of sound

conduction of heat

Solution

Question 6

Real Image

Virtual Image

Both A and B

Neither A nor B

Solution

Question 7

Angle of emergence = angle of incidence

Emergent ray is parallel to incident ray

Behaviour is similar to glass slab in air

All of the above

Solution

Question 8

that the incident ray, the normal at the point of incidence and the refracted ray, all lie in the same plane.

that for a given pair of media and given colour of light, the ratio of the sine of angle of incidence to the sine of angle of refraction is constant.

both A and B

neither A nor B

Solution

Question 9

Angle of refraction = Angle of incidence

Angle of refraction > Angle of incidence

Angle of refraction < Angle of incidence

Angle of refraction $$\geq$$ Angle of incidence

Solution

Question 10

hit the fish

miss the fish

hit but fish will not die

may hit or miss depending on the bullet

Solution

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