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Basic Science Test 9

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Basic Science Test 9
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The term 'ecosystem' represents a group of living organisms, non-living things such as air, water and soil, and their interaction in the habitat in which they live and thrive. Who first coined the term ecosystem?
    Solution
    The term ecosystem was first used in 1935 in a publication by British ecologist Arthur George Tansley. He was a pioneer in the science of ecology.
  • Question 2
    1 / -0
    What does the chemical symbol Fe stand for?
    Solution

  • Question 3
    1 / -0
    A liquid is following in a horizontal pipe of non-uniform cross section. Which of the following quantities remain change with respect to time ?
    Solution
    $$\dfrac{1}{2}\rho v_{1}^{2}+P_{1}+\rho gh=$$ Constant $$\rightarrow$$ Bernalli's eq
    $$K.E.$$ per unit volume of fluid
    Pressure energy per unit volume
    Gravitational $$P.E.$$ per unit volume (w.r.t of ref)
    speed of flow will change
    $$K.E.$$ depends on speed $$\rightarrow K.E.$$ will change
    $$\dfrac{1}{2}\rho v_{1}^{2}+P=$$ constant
         This will also change
  • Question 4
    1 / -0
    The basic elements of all organic compounds is:
    Solution
    The basic element of all organic compounds is Carbon. And they are called organic because they associate with living organisms. 
    So the correct option is 'carbon'.
  • Question 5
    1 / -0
    Which of the following is not part of ecological modernization theory?
  • Question 6
    1 / -0
    The acceleration -time graph of a particle moving in a straight line is as shown in figure. The velocity of the particle at time t=0 in a m/s. The velocity after 2 seconds will be

    Solution
    The velocity after 2 seconds will be the area under the curve of the Acceleration-time graph.
    Area at $$2s = \dfrac{1}{2} \times h \times b = \dfrac{1}{2} \times 4 \times 2 = 4\,m/s.$$
  • Question 7
    1 / -0
    A sphere of mass m is held between two smooth inclined walls. For $$\sin 37^\circ=\frac{3}{5},$$ the normal reaction of the wall (2) is equal to

    Solution
    In horizontal duration

    $$T_{2} \sin(2 \times 37^\circ) = T_{1} \sin37^\circ$$

    $$2T_{2} \sin37^\circ \cos37^\circ = T_{1}\sin37^\circ$$

    $$2 \times T_{2} \times \dfrac{4}{5} = T_{1}$$

    $$T_{1} = \dfrac{8T_2}{5}$$

    Now in vertical direction

    $$T_{1}\cos37^\circ = mg + T_{2} \cos(2 \times 37^\circ)$$

    $$\dfrac{8}{5}T_{2} \times \dfrac{4}{5} = mg + T_{2} \times (-1 + 2\cos^237^\circ)$$

    $$\dfrac{32}{25}T_{2} = mg + T_{2} (-1 + 2 \times (\dfrac{4}{5})^2 )$$

    $$= \dfrac{32}{25}T_{2} = mg + T_{2} \left ( \dfrac{32}{25} - 1 \right )$$

    $$\dfrac{32}{25}T_{2} = mg + \dfrac{7T_2}{25}$$

    $$\dfrac{32 - 7}{25}T_{2} = mg$$

    $$\dfrac{25}{25}T_{2} = mg$$

    $$T_{2} = mg$$

  • Question 8
    1 / -0
    Invention means
  • Question 9
    1 / -0
    A $$0.4\ kg$$ body is rotated with a constant angular speed of $$2\ rps$$ in a vertical circle of radius $$1.2\ m$$ with the help of a string. The tension in the string when it is at the highest point is
    Solution
    So, $$IQT=\dfrac {mv^2 }{R}-mg$$
    Now, $$W=2z\times 2=4x$$
    So, $$T=mw^2R-mg$$
    $$=0.4\times 16 z^2 \times 1.2-0.4\times 10$$
    $$=16\times 4\times 1.2-4$$
    $$=72.8$$

  • Question 10
    1 / -0
    A body partially floats in wafer when
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