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Mensuration Test - 2

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Mensuration Test - 2
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The number of paving stones, each measuring 10 dm by 9 dm required to pave a rectangular veranda 60 m by 6 m is _________.

    Solution

    Area of each paving stone =(10×9) dm2 = 90 dm2 Now, length of veranda = 60 m = 600 dm Breadth of veranda = 6 m = 60 dm ∴Area of veranda = (600 × 60) dm2 = 36000 dm2 ∴ Required number of paving stones = 36000/90 = 400

  • Question 2
    1 / -0

    Find the distance travelled by Priya, if she takes 4 rounds of equi-triangular park of side 105 cm.

    Solution

    Length of the side of the park = 105 cm Perimeter of equi-triangular park=3×105 = 315 cm ∴ Distance covered by Priya in 4 rounds =4×315=1260 cm

  • Question 3
    1 / -0

    Latika wants to put a border around her bedsheet of length 10 m and breadth 5 m60cm. Find the total cost of the border required at the rate of Rs. 90 per metre.

    Solution

    Length of bed-sheet = 10 m Breadth of bed-sheet = 5 m 60 cm = 5.6 m Perimeter of bed-sheet = 2(10 + 5.6) =2×(15.6)=31.2m Cost of 1 m border = Rs. 90 ∴ Total cost = Rs.(90×31.2)=Rs. 2808

  • Question 4
    1 / -0

    The area of a square is numerically equal to the perimeter of the square, then the side of square is _________.

    Solution

    We have, Perimeter of square = Area of square ⇒ 4 × side = side × side ⇒ Side = 4 units

  • Question 5
    1 / -0

    Niharika walks thrice around a square field of side 22 m. Girish walks twice around a rectangular field with length 10 m and breadth 12m. Who covers more distance and by how much?

    Solution

    Side of square field = 22 m Perimeter of square field =4×22=88 m Length of rectangular field = 10 m Breadth of rectangular field = 12 m Perimeter of rectangular field =2(10+12) = 2(22) = 44 m ∴ Distance covered by Niharika =3×88 = 264 m And distance covered by Girish =2×44 = 88 m So, Niharika covers more distance than Girish and by (264 - 88) m = 176 m.

  • Question 6
    1 / -0

    If the area of a rectangle is equal to the area of a square and length of the rectangle is equal to the perimeter of the square, then the breadth of rectangle is ________

    Solution

    It is given that, Area of rectangle = Area of square ⇒ l × b = side × side Also, length of rectangle = perimeter of square ⇒ l = 4 × side Now, l × b = side × side ⇒ 4 × side × b = side × side ⇒ b = side 4 ∴ Breadth of rectangle = side ÷ 4

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