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Mensuration Test - 4

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Mensuration Test - 4
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  • Question 1
    1 / -0

    Five square flower beds each of sides 1.2 m are dug on a piece of land 4.8 m long and 4.2 m wide. What is the area of the remaining part of land?

    Solution

    Area of land =4.8×4.2=20.16 m2 Area of 1 flower bed =1.2×1.2=1.44 m2 ∴ Area of 5 flower beds = 5×1.44=7.2 m2 So, area of the remaining part of land =20.16−7.2 = 12.96 m2

     

  • Question 2
    1 / -0

    A table top measures 3 m 15 cm by 90 cm. The perimeter of the top of the table is

    Solution

    Length of top of the table = 3 m 15 cm = (300 + 15) cm = 315 cm Breadth of top of the table = 90 cm ∴ Perimeter = 2(315 + 90) = 2(405) = 810 cm = 8 m 10 cm

     

  • Question 3
    1 / -0

    An athlete takes 15 rounds of a rectangular park, 30 m long and 20 m wide. The total distance covered by him is _________

    Solution

    Length of rectangular park = 30 m Breadth of rectangular park = 20 m ∴ Perimeter of park = 2(30+20) =100 m So, distance covered by the athlete in 15 rounds =15×100=1500 m

     

  • Question 4
    1 / -0

    The length of a rectangle is (3/4)th of its breadth. If its perimeter is 126 m, then its area will be _______.

    Solution

    Let the breadth (b) be x m. ∴ Length (l) =(3/4 x) m Perimeter = 126 m ⇒ 2 (l+b) = 126⇒ 2 (3/4 x+x) = 126 ⇒ 7 x 4 = 63 ⇒ x = 63×4/7 = 36 So, breadth = 36 m and length = 3/4 × 36 = 27m ∴ Area = (36 × 27) m2 = 972 m2

     

  • Question 5
    1 / -0

    The area of a rectangular garden 48 m long is 2160 sq.m. Find the width of the garden.

    Solution

    Let the width of the garden be x m. Length = 48 m Now, area = 2160 sq. m ⇒ 48 × x = 2160 ⇒ x = 2160/48 = 45 So, width of the garden is 45 m.

     

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