Mensuration Test

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Mensuration Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

The perimeter of a rectangle whose length$$(l)$$ and breadth$$(b)$$ are given, is

A
$$2(l+b)$$

B
$$2l+b$$

C
$$2l+3b$$

D
None of these

Solution

Perimeter of a rectangle is the sum of all its four sides.

Since, two sides measure $$l$$ and the other two sides measure $$b$$ , Perimeter of a rectangle whose length$$(l)$$ and breadth$$(b)$$ are given, is $$ l + b + l + b = 2(l + b) $$
Question 2
1 / -0

Perimeter of a square is?
Where $$s$$ is the side of the square.

A
$$4s$$

B
$$s^4$$

C
$$4 + s$$

D
$$s \times s$$

Solution

Perimeter of square = 4s
Question 3
1 / -0

Perimeter of a square whose side measures $$4\ m$$ is

A
$$16\ m$$

B
$$16\ cm$$

C
$$4\ m$$

D
$$12\ m$$

Solution

Perimeter of the square side $$ = 4 *side of square $$
Hence, perimeter of this square of side $$4\ m$$ $$ = 4 \times 4 = 16\ m $$
Question 4
1 / -0

If the length and breadth of a rectangle are doubled then its perimeter is

A
tripled

B
doubled

C
made half

D
none of these

Solution

Perimeter of rectangle $$= 2(l+b)$$
Here length $$= l$$ and breadth $$= b$$
If the length and breadth of a rectangle are doubled.
then length $$= 2l$$ and breadth $$= 2b$$
$$\therefore$$ perimeter of new rectangle would be $$ 2(2l+2b) = 4(l+b) = 2.2(l+b)$$
$$\therefore $$ if the length and breadth of a rectangle are doubled then its perimeter is also doubled.
Option B is correct.
Question 5
1 / -0

The perimeter of a square field whose side is $$ 4 \ m$$ is ........... m.

A
$$8$$

B
$$16$$

C
$$12$$

D
$$10$$

Solution

Perimeter of a square is = $$4 \times side$$
Hence Perimeter of square = $$4 \times 4 = 16 m$$
Question 6
1 / -0

Perimeter of a square $$728$$ cm. Then the measure of its side is :

A
$$187$$ cm

B
$$182$$ cm

C
$$128$$ cm

D
$$185$$ cm

Solution

Perimeter of square $$= 4 \times side$$
$$\therefore 4\, \times\, side\, =\, 728$$

$$side\, =\, \displaystyle \frac{728}{4}\, =\, 182\ m$$

Thus the measure of the side of the square is $$182$$ cm.
Question 7
1 / -0

Perimeter of a square garden is $$444$$ m. Then its side measures

A
$$101$$ m

B
$$111$$ cm

C
$$111$$ m

D
$$101$$ cm

Solution

Given, perimeter of a square garden is $$444$$ m.
So, perimeter $$= 444 = 4$$ $$\times$$ $$side$$
$$side\, =\, \displaystyle \frac{444}{4}\, =\, 111$$ m
Then sides of a garden measures $$111$$ m.
Question 8
1 / -0

The perimeter of the rectangle whose length = $$25$$ cm, breadth = $$15$$cm is ............ cm.

A
$$40$$

B
$$80$$

C
$$50$$

D
$$81$$

Solution

Perimeter of a rectangle $$=$$ $$2 \times (length+breadth)$$

Hence perimeter $$=$$ $$2 \times(25+15)$$

$$=$$ $$80\ cm$$
Question 9
1 / -0

The perimeter of a square is $$144 \text{ m}$$, then the side of the square is …..

A
$$34 \text{ m}$$

B
$$36 \text{ m}$$

C
$$44 \text{ m}$$

D
$$38 \text{ m}$$

Solution

Perimeter of square $$=4\times side$$ $$=144$$
Hence, $$side $$ $$=144 \div 4$$ $$=36 \text{ m}$$
Question 10
1 / -0

The distance covered by a farmer around a field of$$ 120 $$m length and $$80$$ m width is ........... m.

A
$$200$$

B

$$300$$

C
$$400$$

D
$$500$$

Solution

Distance covered by the farmer = perimeter of the filed = $$2\times(length+breadth)$$
= $$2\times(120+80)$$
= $$ 2 \times 200$$
= $$ 400 m$$

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Re-Attempt Weekly Quiz Competition

Mensuration Test - 6

Result

Mensuration Test - 6

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SHARING IS CARING

Question 1

$$2(l+b)$$

$$2l+b$$

$$2l+3b$$

None of these

Solution

Question 2

$$4s$$

$$s^4$$

$$4 + s$$

$$s \times s$$

Solution

Question 3

$$16\ m$$

$$16\ cm$$

$$4\ m$$

$$12\ m$$

Solution

Question 4

tripled

doubled

made half

none of these

Solution

Question 5

$$8$$

$$16$$

$$12$$

$$10$$

Solution

Question 6

$$187$$ cm

$$182$$ cm

$$128$$ cm

$$185$$ cm

Solution

Question 7

$$101$$ m

$$111$$ cm

$$111$$ m

$$101$$ cm

Solution

Question 8

$$40$$

$$80$$

$$50$$

$$81$$

Solution

Question 9

$$34 \text{ m}$$

$$36 \text{ m}$$

$$44 \text{ m}$$

$$38 \text{ m}$$

Solution

Question 10

$$200$$

$$300$$

$$400$$

$$500$$

Solution

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