Mensuration Test

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Mensuration Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

Perimeter of square of sides is

A
$$4*side$$

B
$$\displaystyle side^{4}$$

C
$$4 + side$$

D
$$\displaystyle side\times side$$

Solution

since perimeter is defined as sum of all sides
a square has 4 sides
perimeter of square = s+s+s+s
= 4s
Question 2
1 / -0

Perimeter of a square whose side measures $$4$$ m is:

A
$$16$$ m

B
$$16$$ cm

C
$$4$$ m

D
$$12$$m

Solution

Perimeter of a square = $$4 \times side$$
= $$4 \times 4 = 16 m$$
Question 3
1 / -0

The formula for the perimeter of a rectangle is:

A
$$(l + b)$$

B
$$2(l + b)$$

C
$$2 (l \times b)$$

D
$$(l \times b)$$

Solution

Here, $$ABCD$$ is a rectangle.

Let the length and breadth of the rectangle be $$l$$ and $$b$$ respectively.

$$\therefore \ $$ Perimeter of rectangle $$ABCD=AB+BC+CD+DA$$

$$=l+b+l+b$$

$$=2l+2b$$

$$=2(l+b)$$

$$\therefore\ $$ The formula for the perimeter of a rectangle is $$2(l+b).$$
Question 4
1 / -0

Perimeter of square 728 cm Then the measure of its side is

A
$$81$$ cm

B
$$182$$ m

C
$$128$$ cm

D
$$182$$ cm

Solution

We know that,

$$Peri$$$$=4*side$$

$$ 4\displaystyle \times side \displaystyle = 728$$

$$\displaystyle side= \frac{728}{4}= 182m $$
Question 5
1 / -0

If the length of a rectangle is $$5$$ cm and the breadth of the rectangle is $$12$$ cm then find the area of the rectangle.

A
$$25 cm^{2}$$

B
$$60 cm^{2}$$

C
$$31 cm^{2}$$

D
$$12 cm^{2}$$

Solution

Given: The length of the rectangle is $$5 cm$$ and breadth is $$12 cm$$.

Then area of rectangle $$=length \times breadth=5\times 12$$
$$=60 cm^{2}$$
Question 6
1 / -0

What is formula of perimeter of square ?

A
4 $$\times \,\, side^2$$

B
2 $$\times$$ side

C
2 $$\times \,\, side^2$$

D
4 $$\times$$ side

Solution

if side of a square is $$a$$

then perimeter of square is$$= a+a+a+a=4a$$

Hence option $$' D'$$ is the answer.
Question 7
1 / -0

If the side of a square park is $$5 $$m, then its perimeter is ............

A
$$10$$ m

B
$$25$$ m

C
$$20$$ m

D
$$15$$ m

Solution

Perimeter of the square park = $$4\times side$$
= $$ 4*5 = 20 $$
Perimeter of the square = $$20 m$$
Question 8
1 / -0

Perimeter of a rectangle of length $$l$$ and breadth $$b$$ is__

A
$$2l+ b$$

B
$$\displaystyle l\times b$$

C
$$2 (l + b)$$

D
$$2 (l - b)$$

Solution

Given the length of the rectangle $$=\ l$$
the breadth  of the rectangle $$=\ b$$

perimeter of the rectangle $$=$$ sum of length of all sides of the rectangle
$$=\ l+\ b+\ l+ \ b $$
  $$=2\ l+2\ b $$
  $$=2(\ l+\ b) $$

$$\therefore$$ perimeter of the rectangle $$=2(\ l+\ b) $$
Question 9
1 / -0

Perimeter of a square whose side measures 4 m is

A
16 m

B
16 cm

C
4 m

D
12 m

Solution

We know,
Side of square$$=a=4\ \text{m}$$
Perimeter of a square$$ = 4 \times a$$
$$= 4 \displaystyle \times 4\ \text{m} $$
$$= 16 \ \text{m}$$
Question 10
1 / -0

The distance covered by a farmer around a rectangular field of 120 m length and 80 m width is _____ m.

A
200

B
300

C
400

D
500

Solution

We know that the distance covered would be equal to the perimeter of the rectangle.
$$\therefore Distance = 2\times (l+b) = 2\times (120+80) =400m$$

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Re-Attempt Weekly Quiz Competition

Mensuration Test - 7

Result

Mensuration Test - 7

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SHARING IS CARING

Question 1

$$4*side$$

$$\displaystyle side^{4}$$

$$4 + side$$

$$\displaystyle side\times side$$

Solution

Question 2

$$16$$ m

$$16$$ cm

$$4$$ m

$$12$$m

Solution

Question 3

$$(l + b)$$

$$2(l + b)$$

$$2 (l \times b)$$

$$(l \times b)$$

Solution

Question 4

$$81$$ cm

$$182$$ m

$$128$$ cm

$$182$$ cm

Solution

Question 5

$$25 cm^{2}$$

$$60 cm^{2}$$

$$31 cm^{2}$$

$$12 cm^{2}$$

Solution

Question 6

4 $$\times \,\, side^2$$

2 $$\times$$ side

2 $$\times \,\, side^2$$

4 $$\times$$ side

Solution

Question 7

$$10$$ m

$$25$$ m

$$20$$ m

$$15$$ m

Solution

Question 8

$$2l+ b$$

$$\displaystyle l\times b$$

$$2 (l + b)$$

$$2 (l - b)$$

Solution

Question 9

16 m

16 cm

4 m

12 m

Solution

Question 10

200

300

400

500

Solution

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