Algebra Test

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Algebra Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Aanya got 5 marks in Science test. Her friend Sneha got 'x' marks more than Aanya. How many marks did they get altogether?

A
5 × x

B
5 + x

C
10 + x

D
2x + 5

Solution

Marks obtained by Aanya = 5 Marks obtained by Sneha = x + 5 ∴ Marks obtained by both of them = 5 + (x + 5) = x + 10
Question 2
1 / -0

An algebraic expression 11 - y can be written in statement as _______.

A
11 less than y

B
y less than 11

C
y more than 11

D
y divided by 11

Solution

An algebraic expression 11 - y can be written in statement as y less than 11
Question 3
1 / -0

Jaya's score in Mathematics is 30 more than two third of her score in English. If her score in English is x, find her score in Mathematics.

A
2/3 (x+30)

B
2x/3 + 30

C
2x/3 − 30

D
30 − 2x/3

Solution

Jaya's score in English = x ∴ Jaya's score in Mathematics = 2x/3 + 30
Question 4
1 / -0

Value of x in 14 (x/2 − 2) + 4 = 4 is_______.

A
7

B
4

C
14

D
12

Solution

We have, 14 (x/2 − 2) + 4 = 4
⇒ 14 (x − 4/2 )= 0
⇒ 7(x − 4) = 0
⇒ x − 4 = 0 ⇒ x = 4
Question 5
1 / -0

Ashima bought 23 things from the market. She bought five more jeans than shirts and two fewer watches than jeans. If x represents the number of shirts in total, then which sentence can be used to find how many of each thing are bought?

A
x + (x+5) + (x+3) = 23

B
x + (x−5) + (x−3) = 23

C
(x+5) + (x+3) = 23

D
x + (x+3) = 23

Solution

Number of shirts bought by Ashima = x ∴ Number of jeans bought by her = x + 5 ∴ Number of watches bought by her =(x+5)−2=x+3 ∴ Total number of things bought by her =x+(x+5)+(x+3)=23
Question 6
1 / -0

Which equation justifies the given statement? "Perimeter of an equilateral triangle is three times its side l?

A
l × l × l

B
3 × 3 × 3

C
3 × l

D
3 + l

Solution

Perimeter of an equilateral triangle is three times its side 3 × l
Question 7
1 / -0

The equation _______and 2x + 2 = 0 have the same solution.

A
x − 1 = 0

B
x + 1 = 0

C
x − 2 = 0

D
x + 2 = 0

Solution

x+1=0

⇒x+1−1=0−1

[Subtracting 1 from both sides]

⇒x=−1 ...(i)

and 2x+2=0⇒2x+2−2=0−2

[Subtracting 2 from both sides]

⇒2x=−2⇒x=−1 ?(ii)

Thus, from (i) and (ii), Both equations have the same solution.

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Algebra Test - 4

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Algebra Test - 4

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SHARING IS CARING

Question 1

5 × x

5 + x

10 + x

2x + 5

Solution

Question 2

11 less than y

y less than 11

y more than 11

y divided by 11

Solution

Question 3

2/3 (x+30)

2x/3 + 30

2x/3 − 30

30 − 2x/3

Solution

Question 4

7

4

14

12

Solution

Question 5

x + (x+5) + (x+3) = 23

x + (x−5) + (x−3) = 23

(x+5) + (x+3) = 23

x + (x+3) = 23

Solution

Question 6

l × l × l

3 × 3 × 3

3 × l

3 + l

Solution

Question 7

x − 1 = 0

x + 1 = 0

x − 2 = 0

x + 2 = 0

Solution

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