Ratio and Proportion Test

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Ratio and Proportion Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

The ratio of Rs. 1 to 60 paise is

A
$$5 : 4$$

B
$$5 : 2$$

C
$$5 : 3$$

D
$$1 : 6$$

Solution

Rs$$ 1 = 100 $$paise
$$\displaystyle \therefore $$ Ratio of Rs $$ 1\ to\ 60$$ paise
$$= 100 : 60 = 5 : 3$$
Question 2
1 / -0

In a football match the ratio of total number of players of both the teams to the number of referees is:

A
$$\dfrac{10}{2}$$

B
$$\dfrac{11}{2}$$

C
$$\dfrac{22}{2}$$

D
$$\dfrac{22}{1}$$

Solution

The total number of football player in$$ 1 team=11$$
therefore in 2 teams the player must be $$2\times 11=22$$
and $$refree =1$$
$$ratio=\dfrac{22}{1}$$
Question 3
1 / -0

If the cost of $$x$$ metres of wire is $$d$$ rupees, then what is the cost of $$y$$ metres of wire at the same rate?

A
Rs. $$\displaystyle {\left (\frac{xy}{d} \right )}$$

B
Rs. $$(xy)$$

C
Rs. $$(yd)$$

D
Rs. $$\displaystyle {\left (\frac{yd}{x} \right )}$$

Solution

Cost of $$x$$ metres = Rs. $$d$$
Cost of $$1$$ metre = Rs. $$\left (\displaystyle \frac{d}{x} \right )$$
Cost of $$y$$ metres = Rs. $$\displaystyle {\left (\frac{d}{x}\, \times\, y \right )}$$
= Rs. $$\displaystyle {\left (\frac{yd}{x} \right )}$$
Question 4
1 / -0

In a cricket team the ratio of total number of players to the number of wicket keepers is

A
$$\dfrac{1}{11}$$

B
$$\dfrac{11}{1}$$

C
$$\dfrac{16}{1}$$

D
$$\dfrac{10}{1}$$

Solution

The number of total players are $$11$$ and total wicket keeper=$$1$$
therefore the $$ratio=\dfrac{11}{1}$$
Question 5
1 / -0

In the word MATHEMATICS, the ratio of number of consonants to the number of vowels is

A
$$4 : 7$$

B
$$7 : 4$$

C
$$5 : 6$$

D
$$6 : 5$$

Solution

M T H M T C S consonants = 7
A E A I vowels = 4
con : vow
7 : 4
Question 6
1 / -0

In the word 'proportion', the ratio of number of p's to the number of o's is:

A
$$2 : 3$$

B
$$3 : 2$$

C
$$1 : 3$$

D
$$3 : 1$$

Solution

The number of $$p's=2$$ and number of $$o's=3$$

$$ratio=\dfrac{p}{o}=2:3$$
Question 7
1 / -0

If Rs. $$60$$ is divided into two parts in the ratio $$2: 3$$, then the difference between those two parts is:

A
Rs. $$10$$

B
Rs.$$ 12$$

C
Rs.$$ 5$$

D
none of these

Solution

$$\displaystyle 60\times \frac{2}{5}=Rs.24$$

$$\displaystyle 60\times \frac{3}{5}=Rs.36$$

Difference = 36 - 24 = Rs.12
Question 8
1 / -0

The ratio of the least prime number to the least composite number is:

A
$$1 : 2$$

B
$$2 : 3$$

C
$$1 : 4$$

D
$$1 : 3$$

Solution

Least prime number $$: $$ Least composite number $$= 2 : 4$$$$= 1 : 2$$
Question 9
1 / -0

Ratio is a method of comparing two quantities by

A
Addition

B
Subtraction

C
Division

D
None

Solution

The method of comparing two quantities (numbers, things, etc.) by dividing one quantity by the other is called a ratio.
So Answar is division
Question 10
1 / -0

In the given ratio of $$1 : 6,$$ add $$4$$ to the antecedent and $$2$$ to the consequent. Then the new ratio is

A
$$5 : 6$$

B
$$1 : 8$$

C
$$5 : 8$$

D
$$8 : 5$$

Solution

Given ratio is $$1:6$$
New ratio $$(1+4):(6+2)=5:8$$

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Ratio and Proportion Test - 6

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Ratio and Proportion Test - 6

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Question 1

$$5 : 4$$

$$5 : 2$$

$$5 : 3$$

$$1 : 6$$

Solution

Question 2

$$\dfrac{10}{2}$$

$$\dfrac{11}{2}$$

$$\dfrac{22}{2}$$

$$\dfrac{22}{1}$$

Solution

Question 3

Rs. $$\displaystyle {\left (\frac{xy}{d} \right )}$$

Rs. $$(xy)$$

Rs. $$(yd)$$

Rs. $$\displaystyle {\left (\frac{yd}{x} \right )}$$

Solution

Question 4

$$\dfrac{1}{11}$$

$$\dfrac{11}{1}$$

$$\dfrac{16}{1}$$

$$\dfrac{10}{1}$$

Solution

Question 5

$$4 : 7$$

$$7 : 4$$

$$5 : 6$$

$$6 : 5$$

Solution

Question 6

$$2 : 3$$

$$3 : 2$$

$$1 : 3$$

$$3 : 1$$

Solution

Question 7

Rs. $$10$$

Rs.$$ 12$$

Rs.$$ 5$$

none of these

Solution

Question 8

$$1 : 2$$

$$2 : 3$$

$$1 : 4$$

$$1 : 3$$

Solution

Question 9

Addition

Subtraction

Division

None

Solution

Question 10

$$5 : 6$$

$$1 : 8$$

$$5 : 8$$

$$8 : 5$$

Solution

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