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Playing with Numbers Test - 24

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Playing with Numbers Test - 24
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Weekly Quiz Competition
  • Question 1
    1 / -0
    HCF of $$120, 144$$ and $$216$$ is:
    Solution
    The HCF of $$120,144,216$$ is
    $$120= 2 \times 2 \times 2 \times 3 \times 5 $$
    $$144= 2 \times 2 \times 2 \times 2 \times 3 \times 3 $$
    $$216= 2 \times 2 \times 2\times 3 \times 3 \times 3 $$
    Since, the Common factors are $$2\times 2\times 2\times 3=24$$ 
    Hence, the HCF of $$120,144$$ and $$216$$ is $$24$$.
  • Question 2
    1 / -0
    The numbers which are not multiples of 2 are called
    Solution

    Even numbers are those numbers which are divisible by $$2$$.

    Odd numbers are those numbers which are not divisible by $$2$$.

    Prime numbers are those which have factors $$1$$ and itself.

    Composite numbers are those which have more than $$2$$ factors. 

    Hence, the number which are not multiples of $$2$$ are called odd numbers.
  • Question 3
    1 / -0
    The HCF of $$12$$ and $$24$$ is equal to
    Solution
    $$12 = 2 \times 2 \times 3 $$
    $$24 = 2 \times 2 \times 2 \times 3$$ 
    So, HCF of $$12$$ and $$24$$ is $$12$$.
    So, option B is correct.
  • Question 4
    1 / -0
    The two numbers which have only 1 as their common factor are called ...........
    Solution

  • Question 5
    1 / -0
    The co-prime numbers from the following pairs, is ...........
    Solution

  • Question 6
    1 / -0
    The $$H.C.F$$ of $$18$$ and $$30$$ is equal to
    Solution
    $$18 = 2 \times 3 \times 3$$
    $$30 = 2 \times 3 \times 5$$
    It can be seen that  $$2\times 3$$ is common for both $$18$$ and $$30$$.
    So, $$H.C.F$$ of $$18$$ and $$30$$ is $$6$$.
    So, option A is correct.
  • Question 7
    1 / -0
    Factor $$\displaystyle \times $$ factor is equal to _______.
    Solution
    As the given statement is in the product form
    So, the product of factor is always multiple of numbers.
    Hence, the answer is multiple.
  • Question 8
    1 / -0
    Every number is a ____ and a _____ of itself
    Solution
    As we know that every number is divisible by itself. 
    So, we can say that every number is a factor and a multiple of itself.
  • Question 9
    1 / -0
    The HCF of $$136, 170$$ and $$255$$ is
    Solution

  • Question 10
    1 / -0
    HCF of 24, 36 and 92 is:
    Solution
    The given numbers are $$24,\ 36\ and\ 92$$.
    The HCF of $$24,36,92$$ can be found by factorising all three numbers, as shown below:
    $$24= 2 \times 2 \times 2 \times 3 $$
    $$36= 2 \times 2 \times 3 \times 3 $$
    $$92 =2 \times 2 \times 23 $$
    Now, common factors are $$2$$ and $$2$$
    So, HCF is $$ 2 \times 2=4$$

    Hence, option D is correct.
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