Integers Test

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Integers Test - 20

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Question 1
1 / -0

Every integer less than $$0$$ has the sign.

A
$$+$$

B
$$-$$

C
$$\times$$

D
$$\div$$

Solution

Option $$B$$ is right.
Every integer less than $$0$$ has the negative sign.
Question 2
1 / -0

Number of integers lying between $$-1$$ and $$1$$ is

A
$$1$$

B
$$2$$

C
$$3$$

D
$$0$$

Solution

Option A is right.
Number of integers lying between $$-1$$ and $$1$$ is $$0$$.
Question 3
1 / -0

An integer with positive sign (+) is always greater than

A
$$0$$

B
$$1$$

C
$$2$$

D
$$3$$

Solution

Every positive integer lie to the right of $$0$$ on the number line.
So, all the positive integers are greater than $$0$$

Hence, $$Op-A$$ is true.
Question 4
1 / -0

When a negative integer is subtracted from another negative integer, the sign of the result

A
is always negative

B
is always positive

C
is never negative

D
depends on the numerical value of the integers

Solution

Option $$D$$ is right.
When negative integer is subtracted from another negative integer result depends on the numerical value of the integers.
Question 5
1 / -0

The successor of the predecessor of $$-50$$ is

A
$$-48$$

B
$$-49$$

C
$$-50$$

D
$$-51$$

Solution

Option $$C$$ is right.
Predecessor of $$-50$$ is $$(-50 - 1 = -51)$$ and successor of $$-51$$ is $$(-50 + 1 = -50)$$.
Question 6
1 / -0

The additive inverse of a negative integer

A
is always negative

B
is always positive

C
is the same integer

D
zero

Solution

Let $$-a$$ be the negative integer.

Thus its additive inverse becomes $$-(-a)$$ which is equal to $$a$$.

Hence additive inverse of a negative integer is always positive.

Option $$B$$ is right.
Question 7
1 / -0

Number of even numbers between $$58$$ and $$80$$ is

A
$$10$$

B
$$11$$

C
$$12$$

D
$$13$$

Solution

Option A is right
If a number side to be an even number is must be divisible by $$2$$. Therefore the even number between $$58$$ and $$80$$ are
$$60, 62, 64, 66, 68, 70, 72, 74, 76, 78$$.
So, there are $$10$$ even numbers between $$58$$ and $$80$$
Question 8
1 / -0

When the integers 10, 0, 5, 5, 7 are arranged in descending or ascending order, them find out which of the following integers always remains in the middle of the arrangement.

A
0

B
5

C
-7

D
-5

Solution

The given integers are 10, 0, 5,-5,-7
Descending order: 10, 5, 0,-5,-7
Ascending order: -7,-5, 0, 5, 10Therefore, the integer, which always remains in the middle of the arrangement, is zero (0).
Question 9
1 / -0

On the following number line value ‘zero’ is shown by the point

A
X

B
Y

C
Z

D
W

Solution

Option (c) is correct; in the figure given below, each unit has a value of 5.
Question 10
1 / -0

Which of the following statements is not true?

A
When two positive integers are added, we always get a positive integer.

B
When two negative integers are added, we always get a negative integer.

C
When a positive integer and a negative integer is added we always get a negative integer.

D
None of these

Solution

Option (c) is correct; if we add a positive and a negative integer, may be zero or positive integers obtained, therefore, the statement (c) is false.

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Re-Attempt Weekly Quiz Competition

Integers Test - 20

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Integers Test - 20

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Question 1

$$+$$

$$-$$

$$\times$$

$$\div$$

Solution

Question 2

$$1$$

$$2$$

$$3$$

$$0$$

Solution

Question 3

$$0$$

$$1$$

$$2$$

$$3$$

Solution

Question 4

is always negative

is always positive

is never negative

depends on the numerical value of the integers

Solution

Question 5

$$-48$$

$$-49$$

$$-50$$

$$-51$$

Solution

Question 6

is always negative

is always positive

is the same integer

zero

Solution

Question 7

$$10$$

$$11$$

$$12$$

$$13$$

Solution

Question 8

0

5

-7

-5

Solution

Question 9

X

Y

Z

W

Solution

Question 10

When two positive integers are added, we always get a positive integer.

When two negative integers are added, we always get a negative integer.

When a positive integer and a negative integer is added we always get a negative integer.

None of these

Solution

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